Physical values in the real world have two components: magnitude and

Even if there were some friction on the ice, it is still possible to use conservation of momentum to solve this problem, but you

hjlf

The problem referred to in this question is missing and it is;

Two hockey pucks of identical mass are on a flat, horizontal ice hockey rink. The red puck is motionless; the blue puck is moving at 2.5 m/s to the left. It collides with the motionless red puck. The pucks have a mass of 15 g. After the collision, the red puck is moving at 2.5 m/s, to the left. What is the final velocity of the blue puck?

Answer:

The condition is that p_f - p_i which is the change in momentum will not be equal to zero but equal to the impulse (Ft).

Explanation:

In the problem described, by inspection, we can say that since there is no friction, we have a closed system and thus momentum is conserved.

Since momentum is conserved, we can say that;

Initial momentum(p_i) = final momentum(p_f)

Now, in this question we are told that some friction wants to be introduced on the ice and it's possible to still use conservation of momentum.

From impulse - momentum theory, we know that;

Impulse = change in momentum

Impulse is zero when no force is acting on the ice and we have; 0 = p_f - p_i

This will yield initial momentum = final momentum.

Now, since a force is applied, we know that impulse is; J = F × t

Thus;

Ft = p_f - p_i

Where F is the force due to friction.

Thus, the condition is that p_f - p_i will not be equal to zero

6 0

2 years ago

16. For this table of data, how should the y-axis be labeled (with units)?

vampirchik [111]

Answer:

The y-axis should be labelled as W in Newtons (kg·m/s²)

Explanation:

The given data is presented here as follows;

Mass (kg) ${}$ Newtons (kg·m/s²)

3.2 ${}$ 31.381

4.6 ${}$ 45.1111

6.1 ${}$ 59.821

7.4 ${}$ 72.569

9 ${}$ 89.241

10.4 ${}$ 101.989

10.9 ${}$ 106.892

From the table, it can be seen that there is a nearly linear relationship between the amount of Newtons and the mass, as the slope of the data has a relatively constant slope

Therefore, the data can be said to be a function of Weight in Newtons to the mass in kilograms such that the weight depends on the mass as follows;

W(m) in Newtons = Mass, m in kg × g

Where;

g is the constant of proportionality

Therefore, the y-axis component which is the dependent variable is the function, W(m) = Weight of the body while the x-axis component which is the independent variable is the mass. m

The graph of the data is created with Microsoft Excel give the slope which is the constant of proportionality, g = 9.8379, which is the acceleration due to gravity g ≈ 9.8 m/s²

We therefore label the y-axis as W in Newtons (kg·m/s²)

6 0

2 years ago

Three balls, with masses of 3m,2m and m, are fastened to a massless rod of length L. The rotational inertias about the ledt

Oduvanchick [21]

I = MR^2

The Attempt at a Solution:::

I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2

I total = 3ML^2/2

It says the answer is 3ML^2/4 though.

⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔⛔

mark it as brainliest.... ✌✌✌

8 0

2 years ago

PLEASE ANSWER QUICKLY

Rom4ik [11]

Answer:

a luminous ball of plasma

6 0

2 years ago

The planet in our solar system whose orbit actually brings it inside the orbit of another planet is

Ber [7]

Answer:

Pluto

Explanation:

In our solar system, we have several planet. Pluto is one of the. Pluto is a planet that is highly oval shaped orbit and eccentric that brings it inside the another orbit. It get inside the orbit of Neptune. Sometimes even Neptune get far away from sun in comparison to the dwarf planet Pluto.

It is very strange happening in the world of planet. it occurs in the year of 1979 and 1999. But Pluto never ever crashed into Neptune. It happen because Neptune takes every three lapse that takes around the sun but Pluto makes only two lapse. This happening prevents two bodies from clashes.

7 0

3 years ago