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stich3 [128]
3 years ago
14

How much heat is required to raise the temperature of 250.0 g of mercury by 52 degrees * C with a specific heat of 4.18

Chemistry
2 answers:
Goryan [66]3 years ago
5 0
Heat required = M * C * (delta T)
= (Mass)*(Specific heat)*(temperature change)
= 250 * 4.18* 52 = 54340Joules.

I solve when unit of specific heat is (J/gC) if have another unit please tell me
iogann1982 [59]3 years ago
4 0

Answer:

250*4.18*52=54340

Explanation:

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at standard pressure how do the boiling point and the freezing point of NaCl compare to the boiling point and freezing point of
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Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  H_{2}C_{3}H_{2}OH=0.15-x

Let concentration in equilibrium state ofHC_{3}H_{2}O_{4}^{-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}

x^{2}+0.0015x-0.000225=0

Which is a quadratic equation in x, solving it gives;

x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

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