Answer:
1.44*10^-3m
Explanation:
Given that distance BTW two bright fringes is
DetaY = lambda* L/d
So for second wavelength
Deta Y2= Lambda 2* L/d
=lambda 2 x deta y1/ lambda1
So substituting
= 360 x 10^-9 x (1.6*10^-3/640*10^-9)
1.44*10^ -3m
Answer:
Energy of scattered photon is 232.27 keV.
Kinetic energy of recoil electron is 497.73 keV.
The recoil angle of electron is 13.40°
Explanation:
The energy of scattered photon is given by the relation :
.....(1)
Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon, is mass of electron and θ is scattered angle.
Substitute 730 keV for E₁, 511 keV for and 120° for θ in equation (1).
E₂ = 232.27 keV
Kinetic energy of recoil electron is given by the relation :
K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV
The recoil angle of electron is given by :
Substitute the suitable values in above equation.
= 13.40°
Answer: A,B, and E
Explanation: Just checked I got them right:)
Answer:i=300 mA
Explanation:
Given
inductance(L)=40 mH
Resistor(R)=
Voltage(V)=15 V
Time constant()=
current
Current as a function of time is given by
i= 299.95 mA
Answer:
Explanation:
The fundamental mode of the standing wave in string is expressed as;
fo
F = V/2L where;
V is the speed of the transverse wave
L is the length of the string
Given
V = 40.0m/s
L = 2.00m
F = 40.0/2(2)
F = 40/4
F = 10Hertz
Hence the fundamental mode of the standing wave is 10Hz
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<em>Overtone/harmonics are integral multiples of the fundamental frequency.</em>
Note that 1st overtone is also called second harmonic
Second harmonic
First overtone F1 = 2F
Second overtone/Third harmonics = 3F
First overtone F1 = 2*10
First overtone = 20Hz
3rd harmonic = 3*10
3rd harmonic = 30Hz