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ohaa [14]
3 years ago
15

Find the torque when the work done to more through an angel of 1/4π radians is 3j​

Physics
1 answer:
Basile [38]3 years ago
8 0

Answer:

The torque is approximately 3.82 N·m

Explanation:

The relationship between work done, 'W', and the applied torque, 'τ' can be presented as follows;

W = τ × Δθ

Where;

W = The work done by the torque

τ = The magnitude of the torque

Δθ = The angle through which the object is turned

The parameters for 'W' and 'Δθ' are;

W = 3j

Δθ = 1/4 × π

From W = τ × Δθ, we have;

τ = W/Δθ

∴ τ = 3j/(1/4 × π) ≈ 3.81971863421 N·m

The torque, τ ≈ 3.82 N·m

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Explanation:

Generally, darker colors dominate so a person with one brown-eyed gene and one blue-eyed gene will have brown eyes. The only way to present blue eyes is to inherit two copies of the blue-eyed gene. However, brown-eyed parents can pass a recessive blue-eyed gene. Therefore, two brown-eyed partners can birth a blue-eyed baby.

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What process is used in this example? You have learned that all living things use energy. Your dog is a living thing. She must u
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Electric power is to be generated by installing a hydraulic turbine-generator at a site 70 m below the free surface of a large w
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Answer:

\eta_{turbine} =   0.777 = 77.7\%

\eta_{combined} = 0.728 = 72.8\%

Explanation:

First we calculate the power input to the turbine. The input power will be equal to the potential energy of water per unit time:

Input Power = P_{in} = \frac{Work}{Time} = \frac{Potential\ Energy\ of\ Water}{t} \\P_{in} = \frac{(mass)(g)(height)}{Time} = (mass flow rate)(g)(height)\\\\P_{in} = (1500\ kg/s)(9.81\ m/s^2)(70\ m)\\P_{in} = 1.03\ x\ 10^6\ W = 1030\ KW

Now, for turbine efficiency:

\eta_{turbine} = \frac{Mechanical\ Power\ Out}{P_{in}}\\\\\eta_{turbine} = \frac{800\ KW}{1030\ KW}\\\\\eta_{turbine} =   0.777 = 77.7\%

for generator efficiency:

\eta_{generator} = \frac{Power\ Generation}{Mechanical\ Power\ Out}\\\\ \eta_{generator} = \frac{750\ KW}{800\ KW}\\\\\eta_{turbine} = 0.9375 = 93.75\%

Now, for combined efficiency:

\eta_{combined} = \eta_{turbine}\ \eta_{generator}\\\\\eta_{combined} = (0.777)(0.937)\\\eta_{combined} = 0.728 = 72.8\%

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Thinking Mathematically: Explore the quantitative dependencies of the acceleration upon the speed and the radius of curvature. T
solong [7]

The expression for the centripetal acceleration allows to find the results for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

In circular motion there must be an acceleration towards the center of the circle, it is called cenripetal acceleration, in this case all the energy supplied to the system is used to change the direction of the speed even when its magnitude remains constant.

        a_c = \frac{v^2}{r}  

Where a_c the centripetal acceleration, v is the speed and r the radius of curvature of the circle.

Now we can answer the questions about centripetal acceleration.

A) For the same speed, the acceleration varies INVERSELY with the radius of curvature.

B) For the same radius of curvature the acceleration varies DIRECTLY with the speed.

C) The speed is doubled

         v = 2 v₀

         a_c = \frac{(2v_o)^2 }{r}  

         a_c = 4 \ \frac{v_o^2 }{r}  

The acceleration becomes four times greater than the original value

D) The speed is tripled

         v = 3 v₀

         a_c = 9 \frac{ v_o^2}{r}  

Acceleration becomes nine times greater than the original

E) the radius of curvature is doubled

        r = 2 r₀  

        a_c = \frac{v_o^2}{2 r_o }  

        a_c = \frac{1}{2}  a_o  

Acceleration is reduced to half the original value

F) The radius of curvature is tripled

       r = 3 r₀

       a_c = \frac{v_o^2 }{3 r_o}  \\ \\a_c = \frac{1}{3} a_o  

       

The acceleration is reduced to a third of the initial one.

In conclusion using the expression for the centripetal acceleration we can find the answers for the questions are:

A) The acceleration varies INVERSELY with the radius of curvature.

B) The acceleration varies DIRECTLY with the speed.

C) The acceleration becomes four times greater.

D) The acceleration becomes nine times greater.

E) The acceleration is reduced to half.

F) The acceleration is reduced to a third.

Learn more here: brainly.com/question/6082363

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3 years ago
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