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Rufina [12.5K]
3 years ago
15

calculate the pressure exerted on the floor when a elephant who weighs 6000N stands on 1 foot which has a area of 20m

Physics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

1500n

Explanation:

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Car A (1750 kg) is travelling due south and car B (1450 kg) is travelling due east. They reach the same intersection at the same
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Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

\underset{V_{A}}{\rightarrow} = velocity of car A before collision = 0 i - V_{A} j

\underset{V_{B}}{\rightarrow} = velocity of car B before collision = V_{B} i + 0 j

\underset{V_{AB}}{\rightarrow} = velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j

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M_{B} = mass of car B = 1450 kg

Using conservation of momentum

M_{A}  \underset{V_{A}}{\rightarrow} + M_{B}  \underset{V_{B}}{\rightarrow} = (M_{A} + M_{B}) ( \underset{V_{AB}}{\rightarrow} )

(1750) (0 i - V_{A} j) + (1450) (V_{B} i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) V_{B} i - (1750) V_{A} j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) V_{B} = 97600    and - (1750) V_{A} = - 60160

V_{B} = 67.3 km/h        and  V_{A} = 34.4 km/



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I don't wanna die for them to miss me

Yes, I see the things that they wishin' on me

Hope I got some brothers that outlive me

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Explanation:

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