Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as
= velocity of car A before collision = 0 i - j
= velocity of car B before collision = i + 0 j
= velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j
= mass of car A = 1750 kg
= mass of car B = 1450 kg
Using conservation of momentum
+ = ( + ) ( )
(1750) (0 i - j) + (1450) ( i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)
(1450) i - (1750) j = 97600 i - 60160 j
Comparing the coefficient of "i" and "j" both side
(1450) = 97600 and - (1750) = - 60160
= 67.3 km/h and = 34.4 km/
Answer:
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Explanation:
According to above question ~
Let's find the charge (q) by using formula ~
Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds
the value of force, F=4.0N
Firstly, recall velocity-time equation
Secondly, recall the Newton's 2nd Law
0 Kelvin
Atoms in absolute temperature get approximatelly motionless since 0 Kelvin is -273 degrees Celcius. The kinetic energy of atoms/particles in matter has the possible lowest value ( almost zero), so that there is nothing colder than 0 Kelvin.
η = 40 %
Given that
Qa ,Heat addition= 1000 J
Qr,Heat rejection= 600 J
Work done ,W= 400 J
We know that ,efficiency of a engine given as
Now by putting the values in the above equation ,then we get
η = 0.4
The efficiency in percentage is given as
η = 0.4 x 100 %
Therefore the answer will be 40%.