Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =
√
2.25
2
+
1.05
2
+
2
⋅
2.25
⋅
1.05
cos
90
=
2.48
N
And,this resultant force makes an angle of
tan
−
1
(
1.05
2.25
)
or,
25
degrees w.r.t vertical
Answer:
a. 156.41m
b. directly over the target
Explanation:
a) At the point of release, the weight will have:
Horizontal:
velocity of 40m/s (same as the plane)
Acceleration of zero since it is not under the influence of any force.
Vertical:
initial Velocity - zero at this instant
Acceleration - Towards the ground with g (9.81m/s^2)
from newton's equation of motion, since its falling under gravity, the horizontal component wont be involved
s = ut + (1/2)at^2
u = initial velocity
a = acceleration
s = displacement
t = time taken
75 = 0 + (1/2)(9.81)t^2
t^2=15.29
t=3.91
t = 3.91s
Applying the time of flight to the horizontal components:
Distance = speed x time
= 40 x 3.91
= 156.41m
B) The pilot looks down at the weight after she drops it. Where is the plane located at the instant the weight hits the ground?
not yet over the target
past the target
directly over the target
not enough information to determine
c. directly over the target. will be the correct answer
A. Her mass is 65kg
b. Her weight on Earth is 650N
c. She would weigh 240.5N on Mars
It could easily demonstrate to people how volcanoes explode
Orbital periods of stars in the Galaxy