1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio039 [100]
3 years ago
6

A 60 W light bulb is powered by a connection to a wall outlet with 120 V across the plug terminals. a) What is the current passi

ng thru this resistor?
Physics
2 answers:
Oxana [17]3 years ago
7 0

Answer:

The current through the resistor is 0.5 A

Explanation:

Given;

power of the light bulb = 60 W

voltage in the wall outlet across the plug terminals = 120 V

power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.

power = voltage x current

Current = \frac{power}{voltage} = \frac{60}{120} = 0.5 A

Therefore, for a  60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A

bulgar [2K]3 years ago
5 0

Answer:

0.5 A

Explanation:

Current: The can be defined as the rate of flow of charge around a circuit. The S.I unit of current is Ampere(A)

Using,

P = VI..................... Equation 1

Where P = Power rating of the bulb, V = Voltage of the wall outlet, I = Current passing through the resistor.

Make I the subject of the equation

I = P/V................. Equation 2

Given: P = 60 W, V = 120 V.

Substitute into equation 2

I = 60/120

I = 0.5 A.

Hence the  current passing through the resistor = 0.5 A

You might be interested in
A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to acc
JulsSmile [24]

Answer:

Choice a. 70\; \rm N, assuming that the skating rink is level.

Explanation:

<h3>Net force in the horizontal direction</h3>

There are two horizontal forces acting on the boy:

  • The pull of his friend, and
  • Frictions.

The boy should be moving in the direction of the pull of his friend. The frictions on this boy should oppose that motion. Therefore, the frictions on the boy would be in the opposite direction of the pull of his friend.

The net force in the horizontal direction should then be the difference between the pull of the friend, and the friction on this boy.

\text{Net force, horizontal} = 75\; \rm N - 5\; \rm N = 70\; \rm N.

<h3>Net force in the vertical direction</h3>

The net force on this boy should be zero in the vertical direction. Consider Newton's Second Law of motion. The net force on an object is proportional to its acceleration. In this question, the net force on this boy in the vertical direction should be proportional to the vertical acceleration of this boy.

However, because (by assumption) the ice rink is level, the boy has no motion in the vertical direction. His vertical acceleration will be zero. As a result, the net force on him should also be zero in the vertical direction.

<h3>Net force</h3>

Therefore, the (combined) net force on this boy would be:

\sqrt{(70\; \rm N)^2 + (0\; \rm N)^2} = 70\; \rm N.

4 0
3 years ago
Read 2 more answers
To accurately describe the wind, the measurement should include
joja [24]

Answer:

C. both a speed and a direction

6 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s
bija089 [108]

Answer: Well the answer is KE = 5.625E-7 i just don't know the units for it...

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!!!! :D

3 0
3 years ago
How has technology influenced theories over time?
Contact [7]
Better technology is helping us because we can see more stuff like the microscope we able to make assumptions based on what we saw.  
7 0
3 years ago
An automobile rounds a curve of radius 50.0 m on a flat road.
bixtya [17]

Answer:

14m/s

Explanation:

Given parameters:

Radius of the curve  = 50m

Centripetal acceleration  = 3.92m/s²

Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

r is the radius

  Now insert the parameters and find v;

         v²   = ar

        v² = 3.92 x 50  = 196

         v  = √196 = 14m/s

6 0
3 years ago
Other questions:
  • If a chlorine atom gains or loses a valence electron, it becomes a charged
    6·1 answer
  • Give reason 1.electromagnets are temporary magnets ?
    13·1 answer
  • A laser on the South American plate takes a certain amount of time to reach a satellite and bounce back to Earth. Five years lat
    12·2 answers
  • A bicyclist rides 1.86 km due east, while the resistive force from the air has a magnitude of 5.12 N and points due west. The ri
    6·1 answer
  • Near the surface of Earth, acceleration due to gravity is 9.8 m/s2. Remember the formula: velocity = acceleration x time. Imagin
    6·2 answers
  • What would be the volume of a liquid that has a density of 1.2 g/mL and a mass of 24 grams
    15·1 answer
  • How long does it take for earth to revolve around the sun?
    6·1 answer
  • A Galilean telescope adjusted for a relaxed eye is 36.2 cm long. If the objective lens has a focal length of 39.5 cm , what is t
    13·1 answer
  • Which of these models of the solar system first proved that the sun is at the center of the solar system?
    13·2 answers
  • Dominant alleles are almost always represented with the uppercase form of a letter. True or false?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!