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ahrayia [7]
3 years ago
10

Quinn accelerates her skateboard along a straight path from 0 m/s to 4.0 m/s

Physics
1 answer:
umka2103 [35]3 years ago
8 0
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=2.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{2.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{2.5}

\\ \sf\longmapsto Acceleration=1.6m/s^2

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Answer:

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mv\dfrac{W}{2}= (\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2)\omega_f

\omega_f= \dfrac{mv\dfrac{W}{2}}{\dfrac{1}{3}MW^2 + m(\dfrac{W}{2})^2}

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\tau = Fr

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F = Force

r = Radius

Replacing we have that,

\tau = Fr

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PART B)

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