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ahrayia [7]
3 years ago
10

Quinn accelerates her skateboard along a straight path from 0 m/s to 4.0 m/s

Physics
1 answer:
umka2103 [35]3 years ago
8 0
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=2.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{2.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{2.5}

\\ \sf\longmapsto Acceleration=1.6m/s^2

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A ball is tossed with enough speed straight up so that it is in the air several seconds. Assume upward direction is positive and
Viefleur [7K]

Answer:

Answer:

The velocity of the ball when it reaches its highest point is  0

Explanation:

The velocity of the ball when it reaches its highest point is 0

Once the ball is tossed into the air, as it goes up, the initial velocity with which it was thrown, reduces, as the motion of the ball is hindered by several forces such as gravity and air resistance. This slows down the velocity of the ball, up until it reaches a point, where the upwards velocity of the ball becomes zero. at this point, the ball begins to fall back to the ground.

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3 years ago
How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​
Anon25 [30]

Answer:

5.98 m

Explanation:

T=2\pi \sqrt\frac{L}{g}

T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2) = 11.15*4.6²/(4π²) = 5.98 m

5 0
2 years ago
How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium
Minchanka [31]

The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

<h3>Pressure and temperature at equilibrium </h3>

The relationship between pressure and temperature can be used to determine the height risen by the water.

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where;

  • V₁ = AL
  • V₂ = A(L - y)
  • P₁ = Pa
  • P₂ = Pa + ρgh
  • T₁ = 20⁰C = 293 K
  • T₂ = 10⁰ C = 283 k

\frac{PaAL}{T_1} = \frac{(P_a + \rho gh)A(L-y)}{T_2} \\\\\frac{PaL}{T_1} = \frac{(P_a + \rho gh)(L-y)}{T_2} \\\\L-y = \frac{PaLT_2}{T_1(P_a + \rho gh)} \\\\y = L (1 - \frac{PaT_2}{T_1(P_a + \rho gh)})\\\\y = 4.2(1 - \frac{101325 \times 283}{293(101325\  +\  1000 \times  9.8 \times  100)} )\\\\y = 3.8 \ m

Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

The complete question is below:

A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?

Learn more about thermal equilibrium here: brainly.com/question/9459470

#SPJ4

3 0
2 years ago
Relation of Kilometre and mile​
Alja [10]

Answer:

1km = o.621371 mile

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1.609 kilometers equal 1 mile. The kilometer is a unit of measurement, as is the mille. However, a mile is longer than a kilometer.

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Answer:

the centre

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