Bobo, the clown, can swim at 2.0 m/s. he must make a landing directly across to the north side of the styx river, which is 100.
m wide. the river flows at 6.0 m/s due east at this point. bobo’s biggest problem is that he can only swim while facing due north. how can he possibly make a landing at the desired location?
Bobo's swimming speed = 2.0 m/s Width of the river = 100 m Flowrate of the river = 6.0 m/s due east
First, we need to illustrate the problem. Draw the river with a width of 100 meters. Then, the flow of the river, east at 6 meters per second. Lastly, draw Bobo at one side of the river facing north and an arrow representing swimming speed at 2 meters per second.
Now, we can use the Pythagorean theorem to solve this rate problem.
c^2 = a^2 + b^2
c = speed of Bobo needed a = speed of Bobo facing north b = flow rate of the river going east
c^2 = 2^2 + 6^2
c = 6.32 m / s should be his speed to overcome the current and make a landing at the desired location.
<span>vf^2 = vi^2 + 2*a*d --- vf = velocity final vi = velocity initial a = acceleration d = distance --- since the airplane is decelerating to zero, vf = 0 --- 0 = 55*55 + 2*(-2.5)*d d = (-55*55)/(2*(-2.5)) d = 605 meters
