It will be a physical change
Answer: His weight plus the centripetal force must equal 1170 N
Explanation:
83.0 [g + (v^2 / r)] = 1170
v^2 / 18.0 = (1170 / 83.0) - 9.81
Matter is any substance that has mass and takes up space.
Answer:
Radius of the salami = 9.9 cm
Explanation:
The formula for calculating the radius is given below:
a = v^2/r
where a represents acceleration
v represents velocity
r represents radius
As hungry mouse ran around the salami's circumference with a tangential speed of 0.17 m/s so that means velocity = 0.17 m/s.
The centripetal acceleration of the mouse = 0.29 m/s^2
putting these values in the above formula, we get
0.29 = 0.17^2 / r
After rearranging, we get,
r = 0.17^2 / 0.29
r = 0.099 m
r = 9.9 cm
so the radius of the salami = 9.9 cm
Answer: The workers may come only as far as 0.24m
<em>(Note: The queston is incomplete. Here is the complete question below)</em>
A shielded gamma ray source yields a dose rate of 0.048rad/h at a distance of 1.0m for an average-sized person. If workers are allowed a maximum dose of 5.0 rem in 1 year, how close to the source may they operate, assuming a 35-h work week? Assume that the intensity of radiation falls off as the square of the distance. (It actually falls off more rapidly than 1/r2 because of absorption in the air, so your answer will give a better-than-permissible value.)
Explanation:
Note: 1rem = 1rad
Dose rate per hour from a distance of 1.0m = 0.048rem/h
maximum daily dose in a year for a 35-h week = 5rem/yr / (35h*52*1yr) = 0.0027rem/h.
The required distance is obtained from the <em>inverse square law </em>for radiation<em> which states that the intensity of the radiation </em><em>(I)</em><em> decreases in proportion to the inverse of the distance from the source </em><em>(d)</em><em> squared.</em>
From the law, I₁/I₂ = d₁²/d₂²
Therefore, by knowing the intensity at one distance, one can find the intensity at any other distance.
From the given values I₁ = 0.048rem/h, I₂ = 0.0027rem/h, d₁ = 1.0m, d₂ = ?
d₂² = I₂d₁²/ I₁
d₂² = 0.0027rem/h * (1.0)²/ 0.048rem/h
d₂² = 0.05625m²
d₂ = √(0.05625)
d₂ = 0.24m