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Digiron [165]
3 years ago
6

I want to know if anyone else know how to tell apart real leather from fake leather?!?!

Engineering
2 answers:
kumpel [21]3 years ago
8 0

Answer:

real leather feels more high quality, while fake leather feels like plastic

Explanation:

this comes from experience

Pavel [41]3 years ago
6 0

Answer:

yes i do.

Explanation:

it's pretty easy in my opinion but i dont know about you why do you ask?

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Explain the benefits of reading A vocabulary section at the beginning of a text
Zinaida [17]

Answer: Deatiled information

Explanation:

It helps the reader organize and sort information in the text. It provides detailed information about the content of the text. It prepares readers to look for new vocabulary as they read.

3 0
4 years ago
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A beam spans 40 feet and carries a uniformly distributed dead load equal to 2.2 klf (not including beam self-weight) and a live
salantis [7]

Answer:

A beam is a structural member that is subjected primarily to transverse loads ... stress equal to σy, then the section Moment - Curvature (M-φ) response for .... Example 2.2 Design a simply supported beam subjected to uniformly distributed dead ... (live load). • Step I. Calculate the factored design loads (without self-weight).

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3 years ago
A gas cylinder system is composed of a cylinder fitted with a piston on which small weights are placed. Given that the initial p
Reika [66]

Answer:

the answer is going to be a I think

4 0
4 years ago
What is one experiment that has been done in the manufacturing
Bingel [31]
Do you have a picture of any sort so I can see if there’s any options ;)
8 0
3 years ago
A spherical tank for storing gas under pressure is 25 m in diameter and is made of steel 15 mm thick. The yield point of the mat
nalin [4]

Answer:

a) (option B) 230 kPa

b) (option A) 100 N/m

Explanation:

Given:

Diameter, d = 25 m

Thicknesses, t = 15 mm

Yield point = 240 MPa

Factor of safety = 2.5

a) To find the maximum internal pressure, let's use the formula:

\sigma l = \frac{\sigma y}{FOS} = \frac{PD}{4t}

\frac{\sigma y}{FOS} = \frac{PD}{4t}

Solving for P, we have:

P = \frac{\sigma y * 4t}{FOS * D}

P = \frac{240 * 4 * 15}{2.5 * 25}

P = 230.4 kPa

≈ 230 kPa

The maximum permissible internal pressure is nearly 230kPa

b) Given:

Thickness, t = 6.35 mm

L = 203 mm

Torque, T = 8 N m

Let's find the mean Area,

mA = (l - t)²

= (203 - 6.5)²

= 38671.22mm²

≈ 0.03867 m² (converted to meters)

To find the average shear flow, let's use the formula:

q = \frac{T}{2* mA}

= \frac{8}{2 * 0.03867}

q = 103.4 N/m approximately 100N/m

The average shear force flow is most nearly 100 N/m

4 0
3 years ago
Read 2 more answers
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