Answer:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
The system ball-pin is modelled by the Principle of Moment Conservation:
![(9\,kg)\cdot (15\,\frac{m}{s} ) + (0.85\,kg)\cdot (0\frac{m}{s} ) = (9\,kg)\cdot v + (0.85\,kg)\cdot (45\,\frac{m}{s} )](https://tex.z-dn.net/?f=%289%5C%2Ckg%29%5Ccdot%20%2815%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%280%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%3D%20%289%5C%2Ckg%29%5Ccdot%20v%20%2B%20%280.85%5C%2Ckg%29%5Ccdot%20%2845%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29)
The velocity of the bowling ball after the collision is:
![v = 10.75\,\frac{m}{s}](https://tex.z-dn.net/?f=v%20%3D%2010.75%5C%2C%5Cfrac%7Bm%7D%7Bs%7D)
r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC
The answer is B
because if you compare a regular road and ice... ice is smoother and therefore has less friction
Answer:
Conductors.
Explanation:
Conductors allow the flow of electrons i. e. the current and where some of the electrons energy gets converted into heat while some electrons energy converted into light. Conductors are the materials which has the ability to allow heat and electricity to flow through them. Metals such as gold, copper, Silver, Aluminum, Mercury, Steel, Iron and salty water etc are good conductors of heat and electricity.
Answer:
r = 0.02 m
Explanation:
from the question we have :
speed = 1 rps = 1x 60 = 60 rpm
coefficient of friction (μ) = 0.1
acceleration due to gravity (g) = 9.8 m/s^{2}
maximum distance without falling off (r) = ?
to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force
mv^2 / r = m x g x μ
v^2 / r = g x μ .......equation 1
where
velocity (v) = angular speed (rads/seconds) x radius
angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm
angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds
now
velocity = 6.28 x r = 6.28 r
now substituting the value of velocity into equation 1
v^2 / r = g x μ
(6.28r)^2 / r = 9.8 x 0.1
39.5 x r = 0.98
r = 0.02 m