Ask question

Ask question

All categories

2 years ago

7

Providing trademark protection

2 answers:

beks73 [17]2 years ago

7 0

The 5 Things You Must Do to Protect Your Trademark
1. Do Your Homework. The USPTO won't register your trademark if there is a “likelihood of confusion" with another registered trademark. ...
2. Prepare and File a Trademark Application. ...
3. Respond Promptly to Office Actions or Oppositions. ...
4. Monitor Your Trademark. ...
5. Maintain Your Trademark.

romanna [79]2 years ago

5 0

Answer:

what are you asking exactly?

You might be interested in

If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the

lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

$F=k\cdot x$

We solve for k (spring constant):

$k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}$

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

$\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}$

The work required is 250 joules.

5 0

1 year ago

The instantaneous velocity of an object is the Blank of the object with a Blank.

Ghella [55]

The intaneuos velocity of an object is the

8 0

3 years ago

She has to complete 4 laps around the track which is 400 it took her 6 minutes to complete which best describes her speed and ve

I am Lyosha [343]

Her speed is 4.4 m/s and her velocity is 0 m/s

5 0

3 years ago

Wich process uses cyanide to extract gold

Dvinal [7]

Gold cyanidation, aka MacArthur-Forrest process.

4 0

3 years ago

A father racing his son has half the kinetic energy of the son, who has half the mass of the father.The father speeds up by 1.0

Helga [31]

Answer:

(a) $v_f=2.414\ m.s^{-1}$

(b) $v_s=4.828\ m.s^{-1}$

Explanation:

Let:

mass of father be, $m_f$

mass of son be, $m_s=\frac{m_f}{2}$

speed of son be, $v_s$

initial speed of father be, $v_f$

After speeding up, speed of father is $v_f+1$

<u>We know Kinetic Energy is given as</u>

$KE=\frac{1}{2} m.v^2$ .....................................(1)

where:

m = mass

v = velocity

Hence, according to the initial condition the father is having kinetic energy half the kinetic energy of the son.

$KE_s=2.KE_f$

$\frac{1}{2} m_s.v_s^2=2\times \frac{1}{2} m_f.v_f^2$

$(\frac{m_f}{2})\times v_s^2=2\times m_f\times v_f^2$

$v_s=2v_f$ .................................................(2)

According to the final condition:

$\frac{1}{2} m_s.v_s^2= \frac{1}{2} m_f.(v_f+1)^2$

$(\frac{m_f}{2})\times v_s^2=m_f.(v_f+1)^2$

$v_s^2=2(v_f+1)^2$

$v_s=\sqrt{2}(v_f+1)$ .....................................................(3)

(a)

From eq. 2 & 3

$2v_f=\sqrt{2}(v_f+1)$

$\sqrt{2}\ v_f=(v_f+1)$

$v_f(\sqrt{2}-1)=1$

$v_f=\frac{1}{(\sqrt{2}-1)}$

$v_f=2.414\ m.s^{-1}$

(b)

<em>putting the above value in eq. (2)</em>

$v_s=4.828\ m.s^{-1}$

4 0

3 years ago