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Assoli18 [71]
3 years ago
13

In order to create a charged object, you need to ________.

Physics
1 answer:
Brums [2.3K]3 years ago
7 0
In order to create a charged object you need to transfer electrons either away or to the object by induction, conduction, or friction

Induction is without contact(like bringing a charged object to a electroscope charges the leaves at the bottom)
Conduction is with contact(like the previous answer, wore touching transfers the charge from a source to the object)
Friction(rubbing a balloon on wool)

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Bezzdna [24]

Answer:

Negative

Explanation:

If you have to move the decimal point to the right to get the original number, the exponent will be a positive number, if you have to move the decimal point to the left to get the original number, the exponent will be a negative number.

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8 0
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A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 38 m/s when i
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A rock hanging from a string has a net force of zero acting on it ? true or false ?
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Answer:

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3 years ago
Which of the following happens when a substance melts?
Bess [88]

Answer:

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Explanation:

3 0
3 years ago
EMERGENCY!! Doing my Physics homework now and I need help on this one please - all information provided, I'd be very VERY gratef
IrinaK [193]

(a) The vertical motion is accelerated by gravity. The horizontal component is constant (neglecting air resistance, if this is not a projectile motion, the horizontal component would also be accelerated)

(b) Vertical:

v_y = 30\sin 40^\circ = 19.3\frac{m}{s}

Horizontal:

v_x = 30\frac{m}{s}\cos 40^\circ = 23.0 \frac{m}{s}

(c) Use the kinematic equation for distance. Calculate only the vertical component (horizontal is irrelevant):

s_y = -\frac{1}{2}gt^2 +vt\,,\,\,\,s_y=0\\0 = -\frac{1}{2}gt^2 +vt\\\frac{1}{2}gt =v\\t = \frac{2v}{g}= \frac{2\cdot30\sin 40^\circ\frac{m}{s}}{9.8\frac{m}{s^2}}=3.9s

The ball will be in the air for about 3.9 s.

(d) The range is the horizontal distance traveled. We know the ball is in the air for 3.9s and it moves with a horizontal velocity of 23 m/s. So:

s_x = 23\frac{m}{s}\cdot 3.9 s = 89.7m

The range is 89.7 meters.

6 0
3 years ago
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