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sattari [20]
3 years ago
13

A rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of

3.25 metric tons to a speed of 10,000 m/s. It has an engine and fuel designed to produce an exhaust speed of 2400 m/s. How much fuel plus oxidizer is required (in metric tons)
Physics
1 answer:
choli [55]3 years ago
4 0

Answer:

<em>13.54 tons</em>

Explanation:

Let f be the amount of fuel oxidizer needed

v be the speed

The relationship between them is inverse in nature i.e

f ∝ 1/v

f = k/v

If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v  = 10,000

Substitute and get k

k = fv

k = 3.25 * 10,000

k = 32500

To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s

Recall that f = k/v

f = 32500/2400

f = 13.54 metric tons

<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>

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Answer:

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Answer:

See below

Explanation:

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 when it hits ground this = 0

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     use this value of 't' in the equation to calculate max height = 50.1 m

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        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

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2 years ago
Please help asap asap<br> wdtwygcbhyeegdlu tcgbihjlnkdm;fnbkhjg hv
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When the biker is at the top of the ramp, he has a speed of 10 m/s at
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Tpy6a [65]

Answer:

The wavelength of the light decreases as it enters into the medium with the greater optical density.

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Explanation:

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v=\frac{c}{n}

where v is the speed of the ray of light in the material, c is the speed of light in a vacuum, n is the index of refraction of the material, which is larger for a medium with larger optical density. So, from the equation, we see that the larger the optical density, the smaller the speed of the wave.

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5 0
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