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rosijanka [135]
3 years ago
12

What do you think are some differences between sound waves traveling through air versus traveling through water?

Physics
2 answers:
N76 [4]3 years ago
8 0
I agree with the comment on top
mel-nik [20]3 years ago
4 0

Answer:

in water its more slower because of the liquid matter but in air its a gas formaiton so its more quicker

Explanation:

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A girl throws a marshmallow that lands in her friend’s mouth 2 m away. The girl threw the marshmallow at an angle of 30 degrees.
natima [27]

She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.

<h3>What is projectile motion?</h3>

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

Given data;

The marshmallow was thrown at a distance of 2 meters

Range,R =  3 m

Initial velocity,u

The angle at which the marshmallow was thrown,θ = 30°

The acceleration due to gravity,g = 9.81 m/s²

The projectile's motion is divided into two parts: horizontal and vertical motion.

\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R  = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec

Hence, she throws the marshmallow at a speed of 4.76 m/sec.

To learn more about the projectile motion refer to the link;

brainly.com/question/11049671

#SPJ1

4 0
2 years ago
A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

8 0
3 years ago
Who else got stuck on a question and is NOT ready for test return at 2? its 1:58 AAAAAAA​
k0ka [10]
Good luckkkk hope you do well
3 0
3 years ago
You sit at the outer rim of a Ferris Wheel that rotates 2 revolutions per minute (RPM). What would your rotational speed be if y
svetoff [14.1K]
Your rotational speed would still be the same. This is because all parts of the Ferris wheel rotate together. Your linear speed however would change. That is a function of radius. But the question is asking about rotational speed and that does not change in this situation
5 0
3 years ago
Read 2 more answers
If the strings have the same thickness but different lengths, which of the following parameters, if any, willbe different in the
Vinil7 [7]

Answer:

If the strings have same thickness but different lengths then these parameters wave frequency, speed, wavelength will be different in the two strings. so the option d) None of the above is correct.

Explanation:

5 0
3 years ago
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