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3 years ago

(1+4i)−(−16+9i) i will give brailiest no reporting

Engineering

2 answers:

Karolina [17]3 years ago

8 0

Explanation:

(1+4i)-(-16+9i)

1+4i+16-9i

17-5i

The one in the picture:

15-1(12÷4+1)

15-1(3+1)

15-1×4

15-4

Julli [10]3 years ago

6 0

Answer:

The picture is 56 and the written is -12

Explanation:

hard to read tho

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The cost to become a member of a fitness center is as follows: the membership fee per month is $50.00 the personal training sess

NikAS [45]

Answer:

#include <iostream>

using namespace std;

void information(){

cout<<"Welcome to the portal"<<endl;

cout<<"The membership fee per month is $50.00"<<endl;

cout<<"The personal training session fee is $30.00"<<endl;

cout<<"The senior citizens discount is 30%"<<endl;

cout<<"If the membership is bought and paid for 12 or more months, the discount is 15%;"<<endl;

cout<<"If more than five personal training sessions are bought and paid for, the discount on each session is 20%."<<endl;

}

void getInfo(bool &senior, int &months, int &personal){

cout<<"Are you senior citizen y/n ? : ";

char choice;

cin>>choice;

if(choice=='y' || choice=='Y'){

senior = true;

}else{

senior = false;

}

cout<<"Enter number of months for membership : ";

cin>>months;

cout<<"Enter number of personal training session : ";

cin>>personal;

}

double calcCost(bool senior, int months, int personal){

double cost=0;

double memberShipCost=months*50;

double trainingCost=personal*30;

if(personal>5){

trainingCost*=.80; //discount on personal training

}

if(months>=12){

memberShipCost*=.85; //discount on membership

}

cost = memberShipCost+trainingCost;

//discount for seniors

if(senior){

cost = cost*.70;

}

return cost;

}

int main() {

information();

cout<<"Select an option"<<endl;

char choice;

while(true){

cout<<endl<<endl;

cout<<"a. Calculate membership costs."<<endl;

cout<<"b. Quit program."<<endl;

cout<<"Enter your choice : ";

cin>>choice;

bool senior=true;

int months,personal;

if(choice=='a'){

getInfo(senior,months,personal);

double cost=calcCost(senior, months, personal);

cout<<"The calculated cost is $"<<cost<<endl;

}else if(choice=='b'){

break;

}

return 0;

}

Explanation:

8 0

4 years ago

Draw the Pressure - Temperature Diagram showing the liquid and vapor phases, along with the saturation line and the critical poi

yarga [219]

Answer:

Pressure- temperature diagram of the fluid is the phase lines that separate all the phases.

Explanation:

Step1

Pressure temperature diagram is the diagram that represents the all the phases of the fluid by separating a line. There is no phase change region in the pressure temperature diagram out of 15 possible diagrams. There are three lines that separate the phase of the fluid. These three lines are fusion, vaporization and sublimation.

Step2

The intersecting point of these lines is triple point of fluid. Out of 15 possible phase diagram, only pressure temperature diagram has triple point as a point. In other diagrams phase change region is present and triple point is not a point. Critical point is the point in all possible property diagrams.

Pressure temperature diagram is shown below:

5 0

3 years ago

Steel balls 12 mm in diameter are annealed by heating to 1150 K and then slowly cooling to 400 K in an air environment for which

luda_lava [24]

Answer:

It will take the steel 425.925sec to cool from 1150k to 400k

Explanation:

Detailed explanation and calculation is shown in the image

6 0

3 years ago

The input shaft to a gearbox rotates at 2300 rpm and transmits a power of 42.6 kW. The output shaft power is 34.84 kW at a rotat

Marrrta [24]

Answer:

Torque at input shaft will be 176.8695 N-m

Explanation:

We have given input power $P_{IN}=42.6KW=42.6\times 10^3W$

Angular speed = 2300 rpm

For converting rpm to rad/sec we have multiply with $\frac{2\pi }{60}$

So $2300rpm=\frac{2300\times 2\pi }{60}=240.855rad/sec$

We have to find torque

We know that power is given by $P=\tau \omega$ , here $\tau$ is torque and $\omega$ is angular speed

So $42.6\times 10^3=\tau \times 240.855$

$\tau =176.8695N-m$

So torque at input shaft will be 176.8695 N-m

4 0

4 years ago

Engineering stress and strain are calculated using the actual cross-sectional area and length of the specimen. a. True b. False?

Flauer [41]

Answer:

False

Explanation:

True stress and strain are what are calculated by diving applied load by actual cross sectional area and change in length by length of specimen respectively. However, for engineering stress and strain, we use original area and original length. Generally, engineering Stress is always greater than the corresponding True Stress because the actual area increases due to Poisson's effect.

3 0

3 years ago