Answer:
option B is correct. Fracture will definitely not occur
Explanation:
The formula for fracture toughness is given by;
K_ic = σY√πa
Where,
σ is the applied stress
Y is the dimensionless parameter
a is the crack length.
Let's make σ the subject
So,
σ = [K_ic/Y√πa]
Plugging in the relevant values;
σ = [50/(1.1√π*(0.5 x 10^(-3))]
σ = 1147 MPa
Thus, the material can withstand a stress of 1147 MPa
So, if tensile stress of 1000 MPa is applied, fracture will not occur because the material can withstand a higher stress of 1147 MPa before it fractures. So option B is correct.
Answer:
The publication of a parody for commercial gain does not fall within the protection afforded by Section 107, as it is used for commercial gain.
Explanation:
<h2><u><em>
PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
Answer:
Using the above algorithm matches one pair of Ghostbuster and Ghost. On each side of the line formed by the pairing, the number of Ghostbusters and Ghosts are the same, so use the algorithm recursively on each side of the line to find pairings. The worst case is when, after each iteration, one side of the line contains no Ghostbusters or Ghosts. Then, we need n/2 total iterations to find pairings, giving us an P(
)- time algorithm.
Hi! bridges could have been collapse due to an error made by the engineers during construction.
Answer:
A) Upper bound modulus of elasticity; E = 165.6 GPa
B) Lower bound modulus of elasticity; E = 83.09 GPa
Explanation:
A) Formula for upper bound modulus is given as;
E = E_m(1 - V_f) + E_f•V_f
We are given;
E_m = 60 GPa
E_f = 380 GPa
V_f = 33% = 0.33
Thus,
E = 60(1 - 0.33) + 380(0.33)
E = (60 x 0.67) + 125.4
E = 165.6 GPa
B) Formula for lower bound modulus is given as;
E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]
E = 1/[(0.33/380) + ((1 – 0.33)/60)]
E = 1/(0.0008684 + 0.01116667)
E = 1/0.01203507
E = 83.09 GPa
