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3 years ago

What i s the value of a capacitor with 250 V applied and has 500 pC of charge? (a) 200 uF (b) 0.5 pF (c) 500 uF (d) 2 pF

Engineering

1 answer:

exis [7]3 years ago

3 0

Answer:

(d) 2 pF

Explanation: the charge on capacitor is given by the expression

Q=CV

where Q=charge

C=capacitance

V=voltage across the plate of the capacitor

here we have given Q=500 pF, V=250 volt

using this formula C= $\frac{Q}{V}$

=500× $10^{-12}$ × $\frac{1}{250}$

=2× $10^{-12}$

=2 pF

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Explanation:

(a)

Calculating the distance of plate from centre line using the formula;

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d = diameter of flow = 9 mm

Substituting, we have;

h = 9/2

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Substituting into the equation, we have;

Q = (2*0.0045³/3*0.38) *(35000)

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τ = h*(Δp/L)

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We know that for one revolution

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