Question

A stone is dropped from the top a 45m hign building how fast will it moving when it reaches the ground? Ande what will its velocity be?

Answer 1

Answer:

29.7 m/s fast, velocity is 29.7 m/s

Explanation:

Applying,

v² = u²+2gs...................... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.

Given: u = 0 m/s (dropped from height), s = 45 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

v² = 0²+2×9.8×45

v² = 882

v = √(882)

v = 29.7 m/s.

Hence the stone will be moving 29.7 m/s fast and the velocity is also 29.7 m/s