A stone is dropped from the top a 45m hign building how fast will it moving when it reaches the ground? Ande what will its veloc
1 answer:
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Explanation:
Given:
Solving for :
where:
Integrating to get with initial conditions
:
Integrating to get x with initial conditions x(0) = 0:
When t=T:
1 m = 1 000 000 ym
converted other way we can say that:
1 ym =
m
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
m
we have 1,5 ym^2 which means that answer is:
converted other way we can say that:
1 ym =
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
we have 1,5 ym^2 which means that answer is:
Answer:
Vf = 29.4 m/s
h = 44.1 m
Explanation:
Data:
- Initial Velocity (Vo) = 0 m/s
- Gravity (g) = 9.8 m/s²
- Time (t) = 3 s
- Final Velocity (Vf) = ?
- Height (h) = ?
==================================================================
Final Velocity
Use formula:
- Vf = g * t
Replace:
- Vf = 9.8 m/s² * 3s
Multiply:
- Vf = 29.4 m/s
==================================================================
Height
Use formula:
Replace:
Multiply time squared:
Simplify the s², and multiply in the numerator:
It divides:
What is the velocity when falling to the ground?
The final velocity is <u>29.4 meters per seconds.</u>
How high is the building?
The height of the building is <u>44.1 meters.</u>