Answer:
Explanation:
Sum of the side slope = 2 + 1 = 3
Length of first slope = 2/3 X 3.6 = 2 X 1.2 = 2.4m
Lenght of second slope = 1/3 X 3.6 = 1.2m
Area of the trapezoidal channel = (2.4 + 1.2)/2 X 3.6 = 1.8 X 3.6 = 6.48m²
Alternate dept = 50m³/6.48m²= 7.716m
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
class pointType
{
public:
pointType()
{
x=0;
y=0;
}
pointType::pointType(double x,double y)
{
this->x = x;
this->y = y;
}
void pointType::setPoint(double x,double y)
{
this->x=x;
this->y=y;
}
void pointType::print()
{
cout<<"("<<x<<","<<y<<")\n";
}
double pointType::getX()
{return x;
}
double pointType::getY()
{return y;
}
private:
double x,y;
};
int main()
{
pointType p2;
double x,y;
cout<<"Enter an x Coordinate for point ";
cin>>x;
cout<<"Enter an y Coordinate for point ";
cin>>y;
p2.setPoint(x,y);
p2.print();
system("pause");
return 0;
}
Answer:
14,700 J
Explanation:
PE = Mgh = (75 kg)(9.8 m/s²)(20 m) = 14,700 J
Answer
No;
The two flows are not dynamically similar
Explanation: Given
T∞,1 = 800k
V∞,1 = 200m/s
p∞,1 = 1.739kg/m³
T∞,2 = 200k
V∞,2 = 100m/s
p∞,2 = 1.23kg/m³
Size1 = 2 * Size2 (L1 = 2L2) Assumptions Made
α ∝√T
μ∝√T Two (2) conditions must be met if the two flows are to be considered similar.
Condition 1: Similar Parameters must be the same for both flows
Condition 2: The bodies and boundaries must be genetically true. Condition 2 is true
Checking for the first condition...
Well need to calculate Reynold's Number for both flows
And Check if they have the same Reynold's Number Using the following formula
Re = pVl/μ
Re1 = p1V1l1/μ1 Re2 = p2V2l2/μ2 Re1/Re2 = p1V1l1/μ1 ÷ p2V2l2/μ2
Re1/Re2 = p1V1l1/μ1 * μ2/p2V2l2
Re1/Re2 = p1V1l1μ2/p2V2l2μ1
Re1/Re2 = p1V1l1√T2 / p1V1l1√T1
Re1/Re2 = (1.739 * 200 * 2L2 * √200) / (1.23 * 100 * L2 * √800)
Re1/Re2 = 9837.2/3479
Re1/Re2 = 2,828/1
Re1:Re2 = 2.828:1
Re1 ≠ Re2,
So condition 1 is not satisfied Since one of tbe conditions is not true, the two flows are not dynamically similar
