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tatuchka [14]
3 years ago
10

प्रहार का समरूपी भिन्नार्थक शब्द अर्थ के साथ ​

Engineering
1 answer:
Reika [66]3 years ago
3 0

Answer:

uhvdiuuauivhsifuhviudshivuhrwwwwwgyuvrrrrrrvuybgdwdoushduhsfuhdsiufhduisfhsofhuaifhuadsihfuiahfuidhsfiuhdsiufhdsaigsdygfewyihfiewbvhwegfiyerrrgqewfygediyfgdsyifguysdgfyuuaegfuyaeggfuyegwfyugewafuyegwiufggeegfyusdggfsgodqwufyew98fyyy79ewyf7eywf8777etf87tewtf

Explanation:

djhidhfdiushfiudshfui

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Q2: The average water height of an ocean area is 2.5 m high and each wave lasts for an average period of 7 s. Determine (a) the
navik [9.2K]

Answer:

(a) 561.12 W/ m² (b) 196.39 MW

Explanation:

Solution

(a) Determine the energy and power of the wave per unit area

The energy per unit are of the wave is defined as:

E = 1 /16ρgH²

= 1/16 * 1025 kg/ m3* 9.81 m/s² * (2.5 m )²

=3927. 83 J/m²

Thus,

The power of the wave per unit area is,

P = E/ t

= 3927. 83 J/m² / 7 s = 561.12 W/ m²

(b) The average and work power output of a wave power plant

W = E * л * A

= 3927. 83 J/m² * 0.35 * 1 *10^6 m²

= 1374.74 MJ

Then,

The power produced by the wave for one km²

P = P * л * A

= 5612.12 W/m² * 0.35 * 1* 10^6 m²

=196.39 MW

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