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Rina8888 [55]
3 years ago
13

Consider the following example: The 28-day compressive strength should be 4,000 psi. The slump should be between 3 and 4 in. and

the maximum aggregate size should not exceed 1 in. The coarse and fine aggregates in the storage bins are wet. The properties of the materials are as follows:________.
Cement : Type I, specific gravity = 3.15
Coarse Aggregate: Bulk specific gravity (SSD) = 2.70; absorption
capacity = 1.1%; dry-rodded unit weight = 105 lb./ft.3
surface moisture = 1%
Fine Aggregate: Bulk specific gravity (SSD) = 2.67; absorption
capacity = 1.3%; fineness modulus = 2.70;
surface moisture = 1.5%
Engineering
1 answer:
lara [203]3 years ago
8 0
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Reverse engineering is not the process of analyzing an existing product to 5 points
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5 0
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Read 2 more answers
A plane wall of length L, constant thermal conductivity k and no thermal energy generation undergoes one-dimensional, steady-sta
KIM [24]

Answer:

Temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

Heat rate=q A  

Explanation:

We know that for no heat generation and at steady state

\dfrac{\partial^2 T}{\partial x^2}=0

\dfrac{\partial T}{\partial x}=a

T(x)=ax+b

a and are the constant.

Given that heat flux=q

We know that heat flux given as

q=-K\dfrac{dT}{dx}

From above we can say that

a= -\dfrac{q}{K}

Alos given that when x= L temperature is T(L)=T

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b=T+\dfrac{q}{K}L

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T(x)=-\dfrac{q}{K}x+T+\dfrac{q}{K}L

T(x)=\dfrac{q}{k}(L-x)+T

So temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

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