When the handler has reached the point of balance of the animal, they should stop walking so that they may move only one animal at a time. The point of balance for cattle that are being worked with in limited places such as races and chutes is often found at the animal's shoulder, as seen by the diagrams.
This is further explained below.
<h3>What is a chute?</h3>
Generally, Chutes are channels, planes, or passageways that are either vertical or slanted and through which things may be transported using only gravity.
In conclusion, When the handler has reached the point where the animal's point of balance has been crossed, they should stop walking so that they may move just one animal.
As seen in the illustrations, the point of balance for cattle being worked with in restricted spaces like races and chutes is often located at the animal's shoulder.
Read more about chute
brainly.com/question/10976905
#SPJ1
Answer:
Heat
Explanation:
Carnot cycle:
Carnot cycle is the ideal cycle for all working engine .Carnot cycle all processes are reversible.It have fore process Out of two are constant temperature process and other two are isentropic process(reversible adiabatic).
We know that area under T-s diagram represents the heat.
So 
From cycle we can say that


Answer: 133.88 MPa approximately 134 MPa
Explanation:
Given
Plane strains fracture toughness, k = 26 MPa
Stress at which fracture occurs, σ = 112 MPa
Maximum internal crack length, l = 8.6 mm = 8.6*10^-3 m
Critical internal crack length, l' = 6 mm = 6*10^-3 m
We know that
σ = K/(Y.√πa), where
112 MPa = 26 MPa / Y.√[3.142 * 8.6*10^-3)/2]
112 MPa = 26 MPa / Y.√(3.142 * 0.043)
112 = 26 / Y.√1.35*10^-2
112 = 26 / Y * 0.116
Y = 26 / 112 * 0.116
Y = 26 / 13
Y = 2
σ = K/(Y.√πa), using l'instead of l and, using Y as 2
σ = 26 / 2 * [√3.142 * (6*10^-3/2)]
σ = 26 / 2 * √(3.142 *3*10^-3)
σ = 26 / 2 * √0.009426
σ = 26 / 2 * 0.0971
σ = 26 / 0.1942
σ = 133.88 MPa
Hopefully that helps you out and is this for history or science?
Answer:
a) omax=125 MPa
omin=75 MPa
b) Temperature = 1289.6°F
Explanation:
a) The mean stress is:

omax+omin=200 MPa
stress amplitude=50 MPa
omax-omin=50MPa
2omax=250 MPa
omax=125 MPa
omin=75 MPa
b) For copper, the creep is important at 0.65 of the melting point, thus:
Temperature = 0.65*1984°F=1289.6°F