Answer:
The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x N
The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward
Explanation:
given information:
current, I = 3 A
= +6.5 x C
r = 0.05 m
v = 280 m/s
and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:
F = qvB sin θ
where
F = magnetic force (N)
q = electric charge (C)
v = velocity (m/s)
θ = the angle between the velocity and magnetic field
to find B we use
B = μI/2πr
μ = 4π x or 1.26 x N/ , thus
B = 4π x x 3 / 2π(0.05)
= 1.2 x T
Now, we can calculate the magnitude force
F = qvB sin θ
θ = 90°, because the speed and magnetic are perpendicular
F = 6.5 x x 280 x 1.2 x sin 90°
= 2.18 x N
Using the hand law, the magnetic direction is radially inward
Measuring the Volume of Solids. The volume of solids is expressed in cubic measurements, such as cubic centimeter or cubic meter.
Answer:
40 m/s
Explanation:
If you multiply the acceleration with time you get the average speed.