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hichkok12 [17]
3 years ago
9

If you keep adding sugar to water and there comes a point that you cannot dissolve any more sugar into it then this is called?

Chemistry
1 answer:
Sliva [168]3 years ago
4 0

Answer:

the answer is letter D, Dilute solution

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Which element has 13 protons and 8 neutrons?
WINSTONCH [101]

Answer:

only thing close I can see would be aluminun

Explanation:

atomic number of 13 and 8 2nd electrons in its shell.

5 0
3 years ago
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How do you find the molar mass for ba(NO3)2
Korvikt [17]
To find the molar mass<span> of </span>Ba(NO3)2<span>, determine the </span>molar masses of all the atoms that form it. The Molar mass for Barium nitrate is <span>261.337 g/mol.</span>
8 0
3 years ago
When potassium carbonate and calcium chromate are mixed, which of the following will pass through a filter?
aliina [53]

Calcium carbonate will be formed which is insoluble in water.

The answer is a) K and CrO4 only.

8 0
3 years ago
Your calculated density of aluminum is d = 2.69 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign,
stepan [7]

Answer:

0.37 %

Explanation:

Given that:

Calculated density of aluminum = 2.69 g/cm³

Accepted density of aluminum = 2.70 g/cm³

Error\ percentage=\frac {|Accepted\ value-Calculated\ value|}{Accepted\ value}\times 100

Thus, applying values as:

Error\ percentage=\frac {|2.70-2.69|}{2.70}\times 100

<u>Percent error = 0.37 %</u>

7 0
3 years ago
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How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

3 0
3 years ago
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