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Stells [14]
3 years ago
15

a beach ball is left in the bed of a pickup truck. Describe what happens to the ball when the truck accelerates forward

Physics
1 answer:
Zepler [3.9K]3 years ago
8 0
When the truck accelerates forward the ball will shift to the back of the bed of the truck because of inertia
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Mixture are the same throughout
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Changes. :) I think... Whats your question
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3 years ago
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The multi-link mechanism in the Variable Compression Turbo Engine _____, thus varying the compression ratio.
Fittoniya [83]

Answer:

A. Adjusts how far down the piston travels

Explanation:

This type of engine changes the possition of the piston in order to modify the compression chamber volume and therefore the compression ratio of the engine. The volume of the chamber is proportional to the run of the piston (how far down the piston travels)

This engine is used to achive the optimal compression rate in each individual stage.

5 0
3 years ago
Which statement is a description of boyle's law?The temperature and volume of a gas are directly proportional when pressure is c
torisob [31]
P and V are inversely proportional when temperature is constanst.
answer is the last option.


6 0
2 years ago
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Does anyone know the answer to this?
sweet-ann [11.9K]
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*

3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.

Please note that y:x relations are always straight lines while  relations are parabolic lines.

Hope this helps!
5 0
3 years ago
Salmon often jump waterfalls to reach their
Y_Kistochka [10]

Answer:

5.38 m/s

Explanation:

Given (in the x direction):

Δx = 2.45 m

v₀ = v cos 42.5°

a = 0 m/s²

Δx = v₀ t + ½ at²

(2.45 m) = (v cos 42.5°) t + ½ (0 m/s²) t²

2.45 = (v cos 42.5°) t

t = 3.32 / v

Given (in the y direction):

Δy = 0.373 m

v₀ = v sin 42.5°

a = -9.8 m/s²

Δx = v₀ t + ½ at²

(0.373 m) = (v sin 42.5°) t + ½ (-9.81 m/s²) t²

0.373 = (v sin 42.5°) t − 4.905 t²

0.373 = (v sin 42.5°) (3.32 / v) − 4.905 (3.32 / v)²

0.373 = 2.25 − 54.2 / v²

v = 5.38

Graph:

desmos.com/calculator/5n30oxqmuu

4 0
3 years ago
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