Hey there mate!
Please check the attached answer of picture for explanation.

Value of 1.2^2=1.44
value of 2^3+17-3*4=8+17-12=13
value of 9^2/3^3= 81/27=3
(arrange the data set from least to greatest)
0, 0, 2, 2, 3, 4, 6, 8
(find the median: *the middle number*)
Median: 2.5
Lower quartile: 1
Upper quartile: 5
Interquartile range : upper quartile - lower quartile = answer
Interquartile range: 5 - 1 = 4
So the IQR or interquartile for the following data set is 4.