All categories

3 years ago

I need help if someone can help me

Physics

1 answer:

Vinvika [58]3 years ago

3 0

Everything is upside down, and it’s rlly blurry. Sorry

You might be interested in

34. (Double points) You help your friend construct a soap box derby car for the All-American Soap Box derby's Stock Division. He

Elden [556K]

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

Newton's Second Law of Motion states that acceleration (a) happens when a force (F) acts on a mass (m).

We want a car of mass 34.01 kg to have an acceleration of 0.55 m/s². We can calculate the required force using Newton's Second Law of Motion.

F = m × a = 34.01 kg × 0.55 m/s² = 19 N

To accelerate a 34.01 kg-car at 0.55 m/s², a force of 19 N will be required, according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion here: brainly.com/question/25545050

#SPJ1

4 0

2 years ago

What does soil structure refer to?

Zigmanuir [339]

A this refers to the make up of the soil

6 0

4 years ago

Read 2 more answers

Use the data below to compute the gravitational force that the Sun exerts on Jupiter. (Use G = 6.67 x 10^-11 N · m²/kg².)

Mademuasel [1]

The gravitational force on two objects can be determined by the following equation:

$F=G\frac{m_{1}m_{2}}{r^2}$

Where G is the gravitational constant m1 is mass 1, m2 is the second mass nad r^2 is distance between these objects. Therefore, let m1 = mass of Sun 1.99x10^30 kg, m2= mass of Jupiter 1.90x10^27 kg, r is the average distance between the Sun and Jupiter 7.78x10^11 m. By plugging these values in we have:

$F=6.67x10^{-11}\frac{(1.99x10^{30})(1.90x10^{27})}{(7.78x10^{11})^2}$

$F=4.1665x10^{23}$

F=4.17x10^23 N

8 0

3 years ago

Jfdojbfkkjds vdf;ifdfdi

Oliga [24]

Answer:

hsjishhdhjs jdjyshskksndhu

6 0

3 years ago

An object floats in water with 5 8 of its volume submerged. The ratio of the density of the object to that of water is

ki77a [65]

Answer:

$\dfrac{5}{8}$

Explanation:

m = Mass of object = $\rho v$

m' = Mass of water = $\rho' v'$

$\rho$ = Density of object

$\rho'$ = Density of water

Weight of the water displaced is the force in the case of floating objects

According to the question

$v'=\dfrac{5}{8}v$

In the case of floating objects

$W=W'\\\Rightarrow mg=m'g\\\Rightarrow \rho vg=\rho'v'g\\\Rightarrow \rho v=\rho' \dfrac{5}{8}vg\\\Rightarrow \rho=\rho' \dfrac{5}{8}\\\Rightarrow \dfrac{\rho}{\rho'}=\dfrac{5}{8}$

The ratio of the density of the object to that of water is $\dfrac{5}{8}$

3 0

3 years ago