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An aluminum ion has 13 protons, 14 neutrons, and 10 electrons. What is the charge of the aluminum ion?

Kipish [7]

Answer:

+3

Explanation:

-10 + 13 = +3

-10 IS THE NUMBER OF ELECTRONS

13 IS THE NUMBER OF PROTONS

3 0

3 years ago

1.Why mixture of stone pebbles and water is considered a suspension? Write few properties of the suspension. How suspension diff

sergey [27]

Explanation:

1.A mixture of stone, pebbles, and water is an example of a suspension. Because the particle size is more than 1000nm.

Properties of suspensions:

Suspension is a heterogeneous mixture. The constituents of the mixture are clearly visible.

The particle size will be more than 1000nm. If the suspension is left undisturbed then the particles will settle down.

Properties of Colloids:

Whereas in colloidal solutions, the particle size is in between 1nm-1000nm.

The particles will never settle down in colloid.

They show the Tyndall effect.

2.The solubility of salt at 20^oC is 30. That means the maximum amount of salt that is present in 100 g of water is 30 g.

If the temperature of a saturated solution is increased then, its solubility increases or decreases based on the nature of the solute.

For example if we take sodium chloride salt ,then its solubility is not effected by the change in temperature.

For cerium sulphate salt if temperature increases, then its solubility in water decreases.

For sugar (sucrose) its solubility increases with increase in temperature.

8 0

3 years ago

A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7

Hitman42 [59]

Answer:

$P_{tot}=465.27torr$

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

$n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol} =2.00mol$

Next, we calculate such mole fraction as follows:

$x_{O_2}=\frac{2}{6.93+3+2} =0.168$

Then, given the following equation:

$P_{O_2}=P_{tot}*x_{O_2}$

So we solve for the total pressure as follows:

$P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr$

Regards!

6 0

3 years ago

Use the following MO diagram for Be2, Be2+, and Be2-. Based on this diagram,

Marta_Voda [28]

Bond Order = [Σ (bonding e-) - Σ (antibonding e-)]/2
Be2 = 4e = σ1(2e) σ2*(2e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0 
[Be2]+ = 3e = σ1(2e) σ2*(1e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0.5 
[Be2]+ would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order

6 0

3 years ago

Read 2 more answers

A biology student is studying ways to grow crops in soils that are high in salts and other dissolved solids. To determine whethe

lana [24]

Answer:

b. Plants grown in typical soil

Explanation:

The experimental control is one that controls for the condition you have changed. The student was changing the salt concentration. But she has to also grow plants in typical conditions to make sure that the plants are able to grow typically. It ensures that any changes made are the result of the changing experimental conditions, not some other factor.

This controls for unforeseen circumstances, such as that none of the plants grow (maybe the seeds were faulty, maybe the weather was poor). It allows you to make conclusions based on what would have happened if you changed nothing. It is vital for ALL scientific experiments!

5 0

3 years ago