It will be a straight horizontal line on the graph
The figure mentioned on the question is in the attachment.
Answer: a)
= - 38.35N
b)
= 30.5 N
c)
= 27.45 N
d) a = - 13.16 m/s²
Explanation: A block on an inclined plane has 3 forces acting on it:
- Force due to gravity
= m.g; - Normal Force due to the plane;
- Force of Friction
= µ.N;
Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.
The second attachment ilustrate the forces acting on the block.
Calculating:
A) The magnitude of the x-component of Force due to gravity:
According to the second image:
= P.sinθ
= 5.9.8.sin(36.8)
= - 38.35 N
B)
=
= m.g.cosθ
= 5.9.8.cos(36.8)
= 30.5 N
C)
= 0.9.30.5
= 27.45 N
D) For the acceleration, use Newton's Law:
= m . a
If there is movement, it is only on x-axis, so the net force is:
-
= m.a
- 38.35 - 27.45 = 5a
a = - 13.16 m/s²
The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.
Answer:
5.95 ml
Explanation:
Given info
P1=2.9 atm
V1=8.21 ml
P2=4 atm
From Boyle's law we know that p1v1=p2v2 where p and v are pressure and volume respectively. This is at a constant temperature. Making v2 the subject of formula then
V2=p1v1/p2
V2= 2.9*8.21/4=5.95 ml
Answers:
a)The balloon is 68 m away of the radar station
b) The direction of the balloon is towards the radar station
Explanation:
We can solve this problem with the Doppler shift equation:
(1)
Where:
is the actual frequency of the sound wave
is the "observed" frequency
is the velocity of sound
is the velocity of the observer, which is stationary
is the velocity of the source, which is the balloon
Isolating
:
(2)
(3)
(4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.
Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (
) given as data, we can find the distance:
(5)
(6)
Finally:
(8) This is the distance of the balloon from the radar station