Answer:
The frequency of oscillation of the simple pendulum is 0.49 Hz.
Explanation:
Given that,
Mass of the simple pendulum, m = 0.35 kg
Length of the string to which it is attached, l = 1 m
We need to find the frequency of oscillation. The frequency of oscillation of the simple pendulum is given by :
So, the frequency of oscillation of the simple pendulum is 0.49 Hz. Hence, this is the required solution.
Answer:42.4m/s^2
Explanation:
Velocity(v)=6m/s
Radius(r)=0.85 meter
Centripetal acceleration=(v x v) ➗ r
Centripetal acceleration=(6 x 6) ➗ 0.85
Centripetal acceleration=36 ➗ 0.85
Centripetal acceleration=42.4
Well, the force is proportional to the product of the charges
on the two objects. So if the objects are already negatively
charged distance between them is unchanged, then adding
electrons to either or both objects would increase the forces
between them.
The child's linear speed is
<em> (pi / 5) x (the child's distance from the center of the ride, in feet)</em>
feet per second.
The shades are very different
