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balu736 [363]
4 years ago
13

A block with mass m = 5.6 kg is attached to two springs with spring constants kleft = 35 N/m and kright = 52 N/m. The block is p

ulled a distance x = 0.21 m to the left of its equilibrium position and released from rest.
1) What is the magnitude of the net force on the block (the moment it is released)?
Physics
1 answer:
sergeinik [125]4 years ago
4 0

Answer:

the magnitude of the net force on the block is 18.27 N

Explanation:

given information:

mass, m = 5.6 kg

spring constant kleft, k_{l} = 35 N/m

spring constant kright, k_{r} = 52 N/m

x = 0.21 m

the magnitude of the net force on the block. F

F = - kx

  = - (k_{l}+k_{r}) x

  = - (35+52) (0.21)

  = - 18.27 N

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