Answer:
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Explanation:
Step 1: Data given
Kp = 4.7 x 10^3 at 400K
Pressure of CH3OH = 0.250 atm
Pressure of HCl = 0.600 atm
Volume = 10.00 L
Step 2: The balanced equation
CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)
Step 3: The initial pressure
p(CH3OH) = 0.250atm
p(HCl) = 0.600 atm
p(CH3Cl)= 0 atm
p(H2O) = 0 atm
Step 3: Calculate the pressure at the equilibrium
p(CH3OH) = 0.250 - X atm
p(HCl) = 0.600 - X atm
p(CH3Cl)= X atm
p(H2O) = X atm
Step 4: Calculate Kp
Kp = (pHO * pCH3Cl) / (pCH3* pHCl)
4.7 * 10³ = X² /(0.250-X)(0.600-X)
X = 0.249962
p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm
p(HCl) = 0.600 - 0.249962 = 0.350038 atm
p(CH3Cl)= 0.249962 atm
p(H2O) = 0.249962 atm
Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)
Kp = 4.7 *10³
The pressure of CH3OH and HCl will decrease.
The final partial pressure of HCl is 0.350038 atm
Answer: Collide, Collision, Collide, Proper Orientation and Energy
Explanation:
The basic premise of the collision theory is that particles must first collide if a reaction is to occur. Additionally, that collision must be effective. To be effective, the particles must collide with the proper orientation and the proper amount of energy.
Answer: The vapor pressure of water at 10°C will be less as compared with its vapor pressure at 50°C.
Explanation:
Vapor pressure of a liquid is defined as the pressure exerted by the vapors in equilibrium with the liquid/solution at a particular temperature.
As Kinetic energy is dependent on the absolute temperature of the gas.

where R = gas constant
T = temperature
On increase in temperature, the kinetic energy of the molecules increase and thus more liquid molecules can escape to form vapours and thus will exert more vapor pressure.
Thus the vapor pressure of water at 10°C will be less as compared with its vapor pressure at 50°C.
Answer:
41.03 %
Explanation:
Given that,
The actual length of a strip of aluminum is 2.12 m
Observed length of a strip of aluminum is 1.25 m
We need to find the student's percent error. The percentage error on any value is given by :

Putting all values, we get :

So, the percent error of the student is 41.03 %.