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patriot [66]
3 years ago
12

How many moles of H2 are needed to produce 34.8 grams of NH3?

Chemistry
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

6.19g H2

Explanation:

34.8g NH3  |   1 mol NH3/17.04 g NH3  | 3 mol H2/2 mol NH3   | 2.02 g H2/ 1mol H2

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How do you classify a metal
Alenkinab [10]

Answer:

They are solid (with the exception of mercury, Hg, a liquid).

They are shiny, good conductors of electricity and heat.

They are ductile (they can be drawn into thin wires).

They are malleable (they can be easily hammered into very thin sheets).

If this satisfies you please consider giving me brainliest :)

8 0
3 years ago
Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed
Makovka662 [10]

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

7 0
3 years ago
WILL MARK BRAINLY
DENIUS [597]

Answer:

its B i guess

Explanation:

7 0
2 years ago
At STP (101.3 kPa, 0 °C), what volume would 2.00 moles of oxygen gas occupy? The gas constant is 8.31
lakkis [162]

Answer:

44.8 L

Explanation:

Ideal Gas Equation -

i.e.,

PV = nRT

where,

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

Using the information given in the question, Volume of the gas can be calculated -

P = 101.3 kPa

V = ?

n = 2.00 moles

R = 8.31

T = 0 degree C = 273.15 K

Using the above data, and putting the data in the respective formula -

PV = nRT

101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K

V = 44.8 L

Hence, the volume of the given gas = 44.8 L

4 0
3 years ago
250 mL of water is collected during a combustion reaction. The temperature in the
klio [65]

Answer:

10.67 moles is the answers.hope it helped

7 0
3 years ago
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