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3 years ago

I will give u 50 points if u help me

Chemistry

2 answers:

WITCHER [35]3 years ago

7 0

14) gas to liquid to solid
15)chlorine displaces bromine from potassium bromide
16) non-metals
6)vertical
7)similar properties
8)there are patterns
10)decrease
11)very reactive
12) hydrogen
18)lower density than air
19)better insulator
20)metalloids

Fofino [41]3 years ago

6 0

Answer:

a b a

Explanation:

jayfeather friend me

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How to solve 2=-log(x)

ch4aika [34]

First, you want to extract the negative from -log(x).

So now you have log(x) = -2

Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

Then you evaluate the negative square to 1/10^2

Answer is 1/100

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3 years ago

The sum of protons and neutrons in an atom is called the.

tresset_1 [31]

Atomic mass / mass number / atomic weight

(all of which mean the same thing)

6 0

2 years ago

The expression of the theoretical yield (TY) in function of limiting reagent (LR) of a reaction is as follows: TY = ideal mole r

spin [16.1K]

<u>Answer:</u> The theoretical yield of acetanilide is 6.5 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For aniline:</u>

Given mass of aniline = $4.50\times 10^0=4.50g$ (We know that: $10^0=1$ )

Molar mass of aniline = 93.13 g/mol

Putting values in equation 1, we get:

$\text{Moles of aniline}=\frac{4.50g}{93.13g/mol}=0.048mol$

<u>For acetic anhydride:</u>

To calculate the mass of acetic anhydride, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of acetic anhydride = $(1.25\times \text{Mass of aniline})=1.25\times 4.50=5.625mL$

Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

$1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g$

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol$

The chemical equation for the reaction of aniline and acetic anhydride follows:

$C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH$

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = $\frac{1}{1}\times 0.048=0.048mol$ of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = $\frac{1}{1}\times 0.048=0.048mol$ of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

$0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g$

Hence, the theoretical yield of acetanilide is 6.5 grams.

3 0

3 years ago

A closed container holds 2.0 moles of CO2 gas at STP. How many moles of oxygen can be placed in a container of the same size at

PilotLPTM [1.2K]

Answer: 2 moles

Explanation:

STP is Standard Temperature and Pressure. That means the pressure is 1.00 atm and the temperature is 273K. Since the oxygen is placed in the same container, we can use Ideal Gas Law to figure out what container the CO₂ used.

Ideal Gas Law: PV=nRT

P=1.00 atm

n=moles

R=0.08206 Latm/Kmol

T=273K

CO₂

$V=\frac{nRT}{P}$

$V=\frac{(2.0 mol)(0.08206Latm/Kmol)(273K)}{1.00atm}$

$V=44.8L$

Since we know that CO₂ has a 44.8 L container, we can use that to find the moles of oxygen.

$n=\frac{PV}{RT}$

$n=\frac{(1.00atm)(44.8L)}{(0.08206Latm/Kmol)(273K)}$

$n=1.99=2mol$

There are 2 mol of oxygen.

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3 years ago

In 1927, a little-known Belgian priest named Georges Lemaître was the first to propose an expanding universe, based on Einstein’

MatroZZZ [7]

One of the pieces of evidence of the big bang theory where that celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

The big bang is how astronomers explain the way the universe began.

The evidence that I've gathered from the widget that demonstrates that the universe is expanding is that galaxies and other celestial objects are moving away from each other, which is also one of the evidence of the big bang theory where the celestial objects are scattered in the universe because of an explosion that supports the idea of the big bang.

Learn more about the big bang here:

brainly.com/question/18297161

#SPJ1

7 0

2 years ago