Given the necessary information about the two components of projectile motion, your task is to explain the difference or even de
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Answer:
Volume of the sample: approximately .
Average density of the sample: approximately .
Assumption:
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- Volume of the cord is negligible.
Explanation:
<h3>Total volume of the sample</h3>The size of the buoyant force is equal to .
That's also equal to the weight (weight, ) of water that the object displaces. To find the mass of water displaced from its weight, divide weight with
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Assume that the density of water is . To the volume of water displaced from its mass, divide mass with density
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Assume that the volume of the cord is negligible. Since the sample is fully-immersed in water, its volume should be the same as the volume of water it displaces.
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Average density is equal to mass over volume.
To find the mass of the sample from its weight, divide with .
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The volume of the sample is found in the previous part.
Divide mass with volume to find the average density.
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Answer:
New location at time 3.01 is given by: (7.49, 2.11)
Explanation:
Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:
With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:
Therefore, adding these displacements in component form to the original particle's position, we get:
New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)