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Umnica [9.8K]
3 years ago
7

The approximate mass of mercury

Physics
2 answers:
Kamila [148]3 years ago
8 0
3.285 × 10^23 kg
Hope it helps
Maurinko [17]3 years ago
5 0
3.285 × 10^23 kg is the approximate mass of mercury
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A pair of shoes has a mass of .5kg. How much do they weigh on earth?
Masteriza [31]

Answer:

4.9 N

Explanation:

3 0
3 years ago
Energy stores in food would be considered what
Oksana_A [137]

Answer:

Chemical Energy

A Brief Overview Of Chemical Energy

Chemical energy is simply energy that is stored in compounds or elements, specifically in the atomic bonds that connect atoms and molecules. In food, it's a form of potential energy because it's stored away.

Explanation:

8 0
2 years ago
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A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
While using a digital radiography system, suppose a radiographer uses exposure factors of 10 mAs and 70 kVp with an 8:1 grid for
Nimfa-mama [501]

Answer:

b. 12.5 mAs, 70 kVp

Explanation:

The given parameter are;

The initial exposure factors := 10 mAs and 70 kVp

The initial Grid Ratio, G.R.₁ = 8:1

The Grid Ratio with which the radiographer desires to increase the scatter absorption, G.R.₂  = 12:1

Given that the lead content in the 12:1 grid, is higher than the lead content in 8:1 grid and that 12:1 grid needs more mAs to compensate, and provides a higher image contrast, the amount of extra mAs is given by the Grid Conversion Factors, GCF, as follows;

The GCF for G.R. 8:1 = 4

The GCF for G.R. 12:1 = 5

Therefore, given that the mAs used by the radiographer for 8:1 Grid Ratio is 10 mAs, the mAs required for a G.R. of 12:1 in order to maintain the same exposure is given as follows;

mAs for G.R. of 12:1 = 10 mAs × 5/4 = 12.5 mAs

Therefore the new exposure factors are;

12.5 mAs, 70 kVp

5 0
3 years ago
A frictionless spring with a 4-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 30 newtons. If t
maxonik [38]

Answer:

The position for mass is x(t)=36.75sin(37.5t)

Explanation:

Let x(t) donate the position of mass at time t,Then x satisfies the differential equation

m\frac{d^2x}{dt^2} +kx=0\\here\\m=4kg\\k=30N/0.2m\\thus\\w^2=k/m=30N/0.2m*4kg=37.5

The general solution is

(x)t=C_{1}cos(37 .5t)+C_{2}sin(37.5t)

It follows

x'(t)=-37.5C_{1}sin(37.5t)+37.5C_{2}cos(37.5t)\\now\\x(0)=0\\gives\\C_{1}=0\\ and\\x'(0)=1m/s\\gives\\C_{2} =36.75

thus the position of mass is

x(t)=36.75sin(37.5t)

7 0
3 years ago
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