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nata0808 [166]
3 years ago
10

Anybody know how to get minimum wind velocity?

Physics
1 answer:
IRISSAK [1]3 years ago
8 0
Try looking at it like this and I'll bet you'll get it:

You're running through the boxcar on the train at 112 meters per second, but you notice that you're moving along the tracks at 210 meters per second. What must be the speed of the train along the tracks ?
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A ball is thrown downward with an initial speed of 6m/s. the ball's velocity after 4 seconds is m/s. (g=-9.8m/s^2)
7nadin3 [17]

Answer:

8

Explanation:

6 0
3 years ago
an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi
algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

=64N

Hence, Minimum tension and maximum Tension are =64N and 2224N respectively

5 0
3 years ago
The _____ of an object consists of its speed and direction.
ELEN [110]
Velocity would be an answer
3 0
3 years ago
PLZ HURRY!!!
MAVERICK [17]

Answer:

7.8 miles just did it

Explanation:

4 0
3 years ago
A certain kind of glass has an index of refraction of 1.640 for blue light of wavelength 440 nm and an index of 1.595 for red li
seraphim [82]

Answer: 18.27°

Explanation:

Given

Index of refraction of blue light, n(b) = 1.64

Wavelength of blue light, λ(b) = 440 nm

Index of refraction of red light, n(r) = 1.595

Wavelength of red light, λ(r) = 670 nm

Angle of incident, θ = 30°

Angle of refraction of red light is

θ(r) = sin^-1 [(n(a)* sin θ) / n(r)], where n(a) = index of refraction of air = 1

So that,

θ(r) = sin^-1 [(1 * sin 30) / 1.595]

θ(r) = sin^-1 (0.5 / 1.595)

θ(r) = sin^-1 0.3135

θ(r) = 18.27°

4 0
3 years ago
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