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Annette [7]
2 years ago
9

A line passes through the point (2, 7) and has a slope of 4. What is the equation of the line?

Mathematics
1 answer:
mamaluj [8]2 years ago
4 0
Y = mx + b
y = 4x + b
Plug in point
7 = 4(2) + b, b = -1
Equation: y = 4x - 1
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a circle has an area of 225 square inches. if the radius of the circle is multiples by 6, then what is the new area of the circl
Lesechka [4]

Answer:

D:  8,100π in²

Step-by-step explanation:

The formula for area of a circle is

A = πr²

The radius is squared, so if the radius or a new circle is 6 times larger (multiplied by 6), the difference in area will be 36 times greater.  So the area is

225π(36) = 8,100π

3 0
3 years ago
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Aleksandr-060686 [28]
I'm sorry, I don't see the question. Could you please retake the photo in better quality so I could answer it? Thanks!
3 0
3 years ago
Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
1 year ago
3. Buildings A and B are across the street from each other, 35m apart. From a point on the roof of Building A
FrozenT [24]

Answer:

The answer Building B

5 0
2 years ago
X squared + ysquared-6y=-5
Oksanka [162]
Standard Form of the circle:  

x^{2} +(y-3) ^{2} =14

For y:

y=3 (+/-) \sqrt{-x} ^{2}  +14

For x:

x=\sqrt{-y ^{2} } +6y+5

and

- \sqrt{-y}  ^{2} +6y+5
8 0
3 years ago
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