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ruslelena [56]
2 years ago
12

Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes s

oft. What state of matter is the softer wax? Is it possible for the wax to change without changing its state?
Physics
1 answer:
romanna [79]2 years ago
5 0

Answer:

An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.

Explanation:

Hope this helps

May I get braineist pls?

You might be interested in
A string has 8 N of tension. When it is vibrated at 2 Hz, a standing wave forms with a wavelength of 4 cm and an amplitude of 1
Vesnalui [34]

Total distance moved by bead is 1.952 cm.

Explanation:

Let first consider all data that are given in question.

1.    F = 8 N                       ...force acting on string

2.   f  = 2 Hz                     ...frequency of system

3.   β = 4 cm = 0.04 m    ...wavelength of wave formed due to vibration                        

4.   A =  1 cm  = 0.01 m     ...Amplitude of vibration

Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.

Here,it is due to vibration induced in spring due to tension induced in string

Standing wave equation is given by

y=(x,t)= 2A \times sin Kx \times cos(w t)     ...(1)

Let first find, value of K, x, w, t

K=  \frac{2*\pi}{\beta }                   ....(2)

      where β is wavelength in meters

                  K is wave number

K=  \frac{2*\pi}{0.01 }

K=  628.31  \    m^{-1}

now, let us find value of w

w = 2 \times \pi \times f          ....(3)

       where f is frequency in hertz

w = 2 \times \pi \times 2

w = 4 \times \pi

w= 12.5664   rad

now, let us find value of v that is wave speed

v= f \times \beta

v= 2 \times 0.04 \\ v= 0.08 \frac{m}{s}

y=(x,t)= 2A \times sin Kx \times cos(w t)

Notice that some x-positions of the resultant wave are always zero no matter what the phase relationship is.  These positions are called nodes.

Finding the positions where the sine function equals zero provides the positions of the nodes.

sin (K \times x) = 0 \\  K \times x  = \pi , 2\pi ,3\pi ,...

In our case,

K \times x= \pi       and      

x= \frac{\beta }{2}   \\  x= \frac{0.04}{2} \\x= 0.02

y=(0.02,1)= 2A \times sin Kx \times cos(w t)

y=(0.02,1)= 2\times0.01 \times sin \pi \times cos(12.5664 \times 1)

y=(0.02,1)= 2\times0.01 \times (-1) \times 0.9761

y=(0.02,1)=  0.01952  m  = 1.952 cm

Finally, when bead is at middle of the string, total distance after stretch covered  is 1.952 cm.

5 0
3 years ago
A 1500 kg car on flat ground is moving 5.25 m/s. Its engine creates a 1250 N forward force as the car moves 42.8 m. What is its
kari74 [83]

Answer:

9.93 m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 1500 Kg

Initial velocity (u) = 5.25 m/s

Force (F) = 1250 N

Distance (s) = 42.8 m

Final velocity (v) =...?

Next, we shall determine the acceleration of car. This can be achieved as shown below:

Force (F) = mass (m) x acceleration (a)

1250 = 1500 x a

Divide both side by 1500

a = 1250/1500

a = 0.83 m/s²

Therefore, the acceleration of the car is 0.83 m/s²

Now, we can determine the final velocity of car as shown below:

Initial velocity (u) = 5.25 m/s

Distance (s) = 42.8 m

Acceleration (a) = 0.83 m/s²

Final velocity (v) =...?

v² = u² + 2as

v² = (5.25)² + 2 x 0.83 x 42.8

v² = 27.5625 + 71.048

v² = 98.6105

Take the square root of both side

v = √98.6105

v = 9.93 m/s

Therefore, the final velocity of the car is 9.93 m/s

5 0
3 years ago
A piece of copper wire is formed into a single circular loop of radius 9.1 cm. A magnetic field is oriented parallel to the norm
bazaltina [42]

Given Information:  

Radius of circular loop = r = 9.1 cm = 0.091 m  

Change in time = Δt = 0.66 seconds

Change in magnetic field = ΔB = 0.90 T

Resistance of wire per unit length = R = 2.9x10⁻²  Ω/m

Number of turns = N = 1

Required Information:  

Electrical energy dissipated = E = ?  

Answer:  

Electrical energy dissipated = 50.09x10⁻³ Joules  

Step-by-step explanation:  

We know that energy is given by

E = Pt

Where power is given by

P = ξ²/R

Where ξ is the induced EMF in the wire and is given by

ξ = -NΔΦ/Δt

Where ΔΦ is the change in flux and is given by

ΔΦ = ΔBAcosφ

Where φ is the angle between magnetic field and circular loop

A = πr² and R = 2.9x10⁻²*2πr

Substituting the above relations into the energy equation and simplifying yields,

E = [-Nπr²cosφ(ΔB/Δt)²]*t/R

E = [-1*π(0.091)²*cos(0)(0.90/0.66)²*0.66]/2.9x10⁻²*2π*(0.091)

E = 0.050094 Joules

E = 50.09x10⁻³ Joules

Therefore, the average electrical energy dissipated in the circular loop of the wire is 50.09x10⁻³ Joules.

6 0
3 years ago
Pls answer ASAP pls and thnk you my friends
rodikova [14]

Answer:

Since this is old, hope you don't mind if I scoop up these points

Explanation:

6 0
2 years ago
How does surface type affect speed?​
Salsk061 [2.6K]

Answer:

Slick and smooth surfaces mediate friction to a low, allowing an object to speed across it with low resistance.

Explanation:

6 0
2 years ago
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