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Eduardwww [97]
3 years ago
6

How bad of alcoholic do you have to be to have your brain affected​

Chemistry
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

Alcohol in Your Body

Alcohol reaches your brain in only five minutes, and starts to affect you within 10 minutes. After 20 minutes, your liver starts processing alcohol. On average, the liver can metabolize 1 ounce of alcohol every hour.

Explanation:

hope that helps you i just love sharing glmv sorry

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A lack of diversity in a population could possibly cause (2 points)
Natasha_Volkova [10]

The answer is C, Extinction.

If there was no diversity then a single sickness could wipe out a whole population, but if the population was more varied theres a higher chance someone is more resistant to the sickness and could carry on the species life

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Filtration can separate a mixture of fine sand and coarse gravel. The holes in the filter should be large enough to allow ______
Charra [1.4K]

The sand to pass through, but not the gravel. Hope this helps!

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Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac
valentinak56 [21]

Answer : The value of \Delta G_{rxn} is, 8.867kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

Q = reaction quotient

First we have to calculate the \Delta G_^o.

Formula used :

\Delta G^o=-RT\times \ln K_p

Now put all the given values in this formula, we get:

\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})

\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}

Q=8.1\times 10^{5}

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln Q

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})

\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole

Therefore, the value of \Delta G_{rxn} is, 8.867kJ/mole

3 0
3 years ago
Express 749 000 000 in scientific notation,
Dima020 [189]

Answer:

7.49 × 108

Explanation:

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Please I need help with this question.​
7nadin3 [17]

Answer:

c?

Explanation:

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