Que tipo de fermentacion es al mezclar, agua tibia, azucar y pasta dental?

If 1.8 L of water is added to 2.5L of a 7.0 M KOH solution, what is the molarity of the new solution

tatyana61 [14]

Answer : The molarity of the new solution is, 4.069 M

Solution : Given,

Molarity of KOH solution = 4 M

Volume of KOH solution = 2.5 L

Volume of water added = 1.8 L

First we have to calculate the volume of new solution.

Volume of new solution = volume of KOH solution + volume of water added

Volume of new solution = 2.5 L + 1.8 L = 4.3 L

Now we have to calculate the molarity of the new solution.

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of KOH solution

$M_2$ = molarity of new solution

$V_1$ = volume of KOH solution

$V_2$ = volume of new solution

Now put all the given values in the above formula, we get the molarity of the new solution.

$(7M)\times (2.5L)=M_2\times (4.3L)$

$M_2=4.069M$

Therefore, the molarity of the new solution is, 4.069 M

3 0

4 years ago

soaps do not work well in hard waters. But they can still be effected it large quantities of soap are added to water. Explain wh

zmey [24]

The minerals in hard water react with soap and affect its cleaning capacity. It's still possible to use hard water when washing by using more soap. The additional soap will no longer be affected by the minerals in the water, so they can clean just as effectively, but you'll be wasting more soap this way.

8 0

3 years ago

Stock solutions are highly concentrated solutions regularly made in laboratories to reduce preparation time and must be diluted

Paraphin [41]

Answer:

0.9 L.

Explanation:

The following data were obtained from the question:

Molarity of stock solution (M1) = 10 M

Molarity of diluted solution (M2) = 1 M

Volume of stock solution (V1) = 100 mL

Volume of water needed =.?

Next, we shall determine the volume of the diluted solution. This can be obtained as follow:

Molarity of stock solution (M1) = 10 M

Molarity of diluted solution (M2) = 1 M

Volume of stock solution (V1) = 100 mL

Volume of diluted solution (V2) =.?

M1V1 = M2V2

10 × 100 = 1 × V2

1000 = V2

V2 = 1000 mL

Next, we shall determine the volume of water needed. This can be obtained as follow:

Volume of stock solution (V1) = 100 mL

Volume of diluted solution (V2) = 1000 mL

Volume of water needed =?

Volume of water needed = (Volume of diluted solution) – (Volume of stock solution)

Volume of water needed = V2 – V1

Volume of water needed = 1000 – 100

Volume of water needed = 900 mL

Finally, we shall convert 900 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

900 mL = 900 mL × 1 L / 1000 mL

900 mL = 0.9 L

Therefore, the volume of water needed to dilute the solution is 0.9 L.

3 0

3 years ago

Help. Please! Help for 6-13

Lynna [10]

8. Transition metals
9. Halogens
10. Nobel gasses
11. Lanthanides
12. Actinides
13. The tendency of a substance to undergo chemical reaction, either by itself or with other materials, and to release energy.

7 0

3 years ago

Whats factors create surface currents?

AysviL [449]

Answer:

wind direction, landforms, and surface winds.

6 0

3 years ago