30 points to the first correct answer(btw they need to add a simple science subject).

On a playground slide, a child has potential energy that decreases by 1000 J while her kinetic energy increases by 900 J. what o

mel-nik [20]

Answer:

Friction 100 j

Explanation:

Friction causes the inequality between PE and KE

100 J

8 0

2 years ago

Why do areas north of the artic circle in tje northern hemisphere experience a polar day lasting for several months during summe

adell [148]

<span>The regioin is titled towqrd the Sun during polar day. (C)

(The same exact thing happens in areas south of the Antarctic Circle
in the southern hemisphere. The only difference is that the whole thing
is spelled better in the South.)</span>

7 0

3 years ago

Read 2 more answers

Professional application dr. john paul stapp was u.s. air force officer who studied the effects of extreme deceleration on the h

aleksley [76]

A) Acceleration= (282m/s-0m/s)/5.0s= 56.4m/s^2
b) Deceleration=(0m/s-282m/s)/1.40s=201.4m/s^2 (here we reject negative because deceleration already take into account negative)
c) for the first one the multiple will be 5.76g
for the second one it will be 20.6g

5 0

3 years ago

Jennifer, who has a mass of 48.0 kg, is riding at 40.2 m/s in her red sports car when she must suddenly slam on the brakes. An a

Bogdan [553]

Answer:

$F = 3445.714\,N$

Explanation:

The system can be modelled appropriately by the use of the Principle of Momentum Conservation and Impact Theorem:

$(48\,kg)\cdot (40.2\,\frac{m}{s} ) - F\cdot (0.56\,s) = 0\,\frac{kg\cdot m}{s}$

The average force exerted on her:

$F = 3445.714\,N$

3 0

3 years ago

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A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t

kykrilka [37]

Explanation:

It is given that,

Mas of the car, $m_1=1170\ kg$

Initial speed of the car, $u_1=25\ m/s$

Mass of the truck, $m_2=9800\ kg$

Initial speed of the car, $u_2=20\ m/s$

Final speed of the car, $v_1=18\ m/s$

(a) It is a case of elastic collision. Let $v_2$ is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :