Molar mass of N2H4 = 32 grams/mole
<span>3.95 grams of N2H4 = 3.95/32
= 0.123 moles </span>
<span>This will produce 0.123 moles of N2 </span>
<span>Now,
From the gas law equation. </span>
<span>P.V = n x R x T </span>
<span>P = 1 atm (given)
V = </span><span>0.123</span><span> x 0.082057 x 295 </span>
<span>V = 2.97 Liters </span>
<span>Theoretical yield = 2.97 Liters.
Actual yield = 0.750 Liters </span>
percentage yield = (0.75/2.97) x 100 %
= 25.25 %
Answer:
Hey there are you doing are you doing I will tell you the answer
Answer:
c
Explanation:
all fins are for movement
Answer:

Explanation:
Hello,
In this case, the dissociation of the given weak acid is:

Therefore, the law of mass action for it turns out:
![Ka=\frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
That in terms of the change
due to the reaction extent is:

Thus, by solving with the quadratic equation or solver, we obtain:

Which clearly matches with the hydrogen concentration in the solution, therefore, the pH is:

Regards.
The correct answer is <u>C: 0.510 m</u>
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N I C E - D A Y!