To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.
Answer:
0.08 mol L-1
Explanation:
Sulfuric acid Formula: H2SO4
Ammonia Formula: NH3
Ammonium sulfate Formula: (NH₄)₂SO₄
H2SO4 + 2NH3 = 2NH4+ + SO4 2-
H2SO4 + 2NH3 = (NH₄)₂SO₄
H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L
= 0.08 mol L-1
1.) Na
2.) Cl ( at the second blank)
sodium metal+hydrochloric acid
Answer:
Explanation:
mole of O₂ = 
= .25 moles
mole of CO₂
= 
= .1818 moles
moles of SO₂
= .125 moles
Total moles of gas
= .5568 moles.
total volume of gas mixture
= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)
= 12.47 liter.
gas will exert partial pressure according to their mole fraction
gas having greatest no of moles in the total mole will have greatest mole fraction so
O₂ will have greatest partial pressure.
Answer:
48.5 mL , just did it on edge
