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Ede4ka [16]
3 years ago
13

What value of ℓℓ is not allowed for an electron in an n = 3 shell?

Chemistry
1 answer:
dlinn [17]3 years ago
3 0
Every electron shell, designated by "n", has a specific number of electron subshells. The shell number has values equivalent to natural numbers (1, 2, 3, 4...), while the subshells are s, p, d and f.

The subshell that does not exist within the third shell (n = 3) is the f subshell. The energy of the f subshell is too high and cannot be accommodated in the third shell.
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Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o
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<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M

where,

n_p = number of protons

m_p = mass of one proton

n_n = number of neutrons

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We are given:

An isotope of phosphorus which is _{15}^{31}\textrm{P}

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

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Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

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anzhelika [568]
The balanced reaction is:

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<span>
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</span>0.0232 mol NH3 (1 mol N2 / 2 mol NH3) = 0.0116 mol N2


<span>Therefore, the correct answer is A.</span>

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