Question

How many grams of NaOH are contained in 5.0*10ml of a0. 77 sodium hydroxide solution

Answer 1

Answer:

1.54grams

Explanation:

Molarity of a solution = n/V

Where;

n = number of moles (mol)

V = volume (L)

Based on the information given in this question;

Volume of NaOH solution = 5.0 × 10ml

= 50ml = 50/1000 = 0.050 L

Molarity = 0. 77 M

Using; Molarity = n/V

0.77 = n/0.05

n = 0.77 × 0.05

n = 0.0385mol

To find the mass (grams) of NaOH in the solution, we use the following formula:

mole (n) = mass/molar mass

Molar mass of NaOH = 23 + 1 + 16 = 40g/mol

0.0385 = mass/40

mass = 0.0385 × 40

mass = 1.54grams.