Answer:
C-Rb20
Explanation:
The chemical formula for Rubidium oxide is Rb20.
Hope this helps!
P₄0₆
+ 20₂
⇒ P₄0₁₀
Explanation:
The overall equation for the reaction that produces P₄0₁₀ is :
P₄0₆
+ 20₂
⇒ P₄0₁₀
Now let us derive this equation:
Given equations:
P₄
+ 30₂
⇒ P₄0₆
equation 1;
P₄
+ 50₂
⇒ P₄0₁₀
equation 2;
To get the overall combined equation, the equation 1 must be reversed and added to equation 2:
P₄0₆
⇒ P₄
+ 30₂
equation 3
+
equation 2:
P₄
+ 50₂
+ P₄0₆
⇒ P₄0₁₀
+ P₄
+ 30₂
cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;
P₄0₆
+ 20₂
⇒ P₄0₁₀
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Net equation brainly.com/question/2947744
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Okay so because of the difference in density a simple method for telling the difference between the two is to put a sample in a container with oil, because water has a higher density than the oil it would sink to the bottom but alcohol on the other hand is lighter than oil and would float on top of the oil.
However with this question I think that what you would do is use the ice to find out what the substance is, it would float on top of the liquid if it were water because the water is denser than ice but the ice would sink if it was alcohol because the alcohol is less dense than ice.
I hope this helps you, good luck : )
Answer:
1.73 M
Explanation:
We must first obtain the concentration of the concentrated acid from the formula;
Co= 10pd/M
Where
Co= concentration of concentrated acid = (the unknown)
p= percentage concentration of concentrated acid= 37.3%
d= density of concentrated acid = 1.19 g/ml
M= Molar mass of the anhydrous acid
Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1
Substituting values;
Co= 10 × 37.3 × 1.19/36.5
Co= 443.87/36.6
Co= 12.16 M
We can now use the dilution formula
CoVo= CdVd
Where;
Co= concentration of concentrated acid= 12.16 M
Vo= volume of concentrated acid = 35.5 ml
Cd= concentration of dilute acid =(the unknown)
Vd= volume of dilute acid = 250ml
Substituting values and making Cd the subject of the formula;
Cd= CoVo/Vd
Cd= 12.16 × 35.5/250
Cd= 1.73 M
Temperature will raise and water will evaporate