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Tamiku [17]
3 years ago
12

Active listening definition​

Physics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

Active listening is a technique that is used in counseling, training, and solving disputes or conflicts. It requires that the listener fully concentrate, understand, respond and then remember what is being said. This is opposed to other listening techniques like reflective listening and empathic listening.

Explanation:

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On a night when the moon rises at 9 pm, what is its phase?
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Waning Gibbous would be the phase?
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When an object is thrown upwards and reaches its maximum height its speed is: a. Greater than the initial
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Answer:

Option d

Explanation:

When we throw an object in the upward direction, we provide it with certain initial velocity due to which it covers a certain distance up to the maximum height.

While the object is moving in the upward direction, its velocity keeps on reducing due to the acceleration due to gravity which acts vertically downwards in the opposite direction thus reducing its velocity.

So, the maximum height attained by the object is the point where this upward velocity of the body becomes zero and after that the object starts to fall down.

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The number of electrons in a copper penny is approximately 10*10^23. How large would the force be on an object if it carried thi
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3 0
3 years ago
Read 2 more answers
A battery with an internal resistance ofrand an emf of 10.00 V is connected to a loadresistorR=r. As the battery ages, the inter
yanalaym [24]

Answer:

The current is reduced to half of its original value.

Explanation:

  • Assuming we can apply Ohm's Law to the circuit, as the internal resistance and the load resistor are in series, we can find the current I₁ as follows:

        I_{1} = \frac{V}{R_{int} +r_{L} }

  • where Rint = r and RL = r
  • Replacing these values in I₁, we have:

       I_{1} = \frac{V}{R_{int} +r_{L} } = \frac{V}{2*r} (1)

  • When the battery ages, if the internal resistance triples, the new current can be found using Ohm's Law again:

       I_{2} = \frac{V}{R_{int} +r_{L} } = \frac{V}{(3*r) +r} = \frac{V}{4*r}  (2)

  • We can find the relationship between I₂, and I₁, dividing both sides, as follows:

        \frac{I_{2} }{I_{1} } = \frac{V}{4*r} *\frac{2*r}{V} = \frac{1}{2}

  • The current when the internal resistance triples, is half of the original value, when the internal resistance was r, equal to the resistance of the load.  
7 0
3 years ago
. Rohit had only one light source in his room. He was told by his friend that he can make the room more lighted by using mirror.
LUCKY_DIMON [66]

Answer:

very smooth and polished glass mirror

Explanation:

The best type of mirror for this would be a very smooth and polished glass mirror. A metal mirror will also work but it would need to be extremely polished. This would allow light to efficiently be reflected across the room, thus effectively adding an "extra" light source to the room. If the mirror is not smooth then the light may become distorted and not reflect properly as it is supposed to. This may defeat the entire purpose of the mirror for this scenario.

3 0
3 years ago
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